Silver sulfate dissolves in water according to the reaction: Ag2SO4(s) ∆ 2 Ag+(aq) + SO42-(aq) Kc = 1.1 * 10-5 at 298 K A 1.5-L
1 answer:
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Answer :
(a) The mass of produced is, 15.2 grams.
(b) The percent yield of the reaction is, 72.5 %
Explanation :
Part (a) :
Given,
Mass of = 85.1 g
Molar mass of = 27 g/mol
First we have to calculate the moles of
Now we have to calculate the moles of
The balanced chemical equation is:
From the reaction, we conclude that
As, 4 moles of react to give 2 moles of
So, 3.15 moles of react to give
mole of
Now we have to calculate the mass of
Molar mass of = 102 g/mole
Therefore, the mass of produced is, 161.2 grams.
Part (b) :
Now we have to calculate the percent yield of the reaction.
Experimental yield = 116.9 g
Theoretical yield = 161.2 g
Now put all the given values in this formula, we get:
Therefore, the percent yield of the reaction is, 72.5 %
Answer : Hydrogen-bonding, Dipole-dipole attraction and London-dispersion force.
Explanation :
The given molecule is .
Three types of inter-molecular forces are present in this molecule which are Hydrogen-bonding, Dipole-dipole attraction and London-dispersion force.
- Hydrogen-bonding : when the partial positive end of hydrogen is bonded with the partial negative end of another molecule like, oxygen, nitrogen, etc.
- Dipole-dipole attraction : When the partial positively charged part of the molecule is interact with the partial negatively charged part of the molecule. For example : In case of HCl.
- London-dispersion force : This force is present in all type of molecule whether it is a polar or non-polar, ionic or covalent. For example : In case of Br-Br , F-F, etc
Hydrogen-bonding is present between the oxygen and hydrogen molecule.
Dipole-dipole forces is present between the carbon and oxygen molecule.
London-dispersion forces is present between the carbon and carbon molecule.