Answer:
ΔU = - 168 KJ
Explanation:
- ΔU = Q + W.....................first law
∴ W = - 61 KJ........A system performs on its surroundings
∴ Q = - 107 KJ,,,,,,A system release heat
⇒ ΔU = - 107 KJ - 61 KJ = - 168 KJ
Answer:
wheres the map? I can't see it even tho im using my eye glasses
Answer:
5:22 am
Explanation:
The gas X decays following a first-order reaction.
The half-life (
) is 25 min. We can find the rate constant (k) using the following expression.
![k = \frac{ln2}{t_{1/2}} =\frac{ln2}{25min} = 0.028 min^{-1}](https://tex.z-dn.net/?f=k%20%3D%20%5Cfrac%7Bln2%7D%7Bt_%7B1%2F2%7D%7D%20%3D%5Cfrac%7Bln2%7D%7B25min%7D%20%3D%200.028%20min%5E%7B-1%7D)
We can find the concentration of X at a certain time (
) using the following expression.
![[X] = [X]_0 \times e^{-k \times t}](https://tex.z-dn.net/?f=%5BX%5D%20%3D%20%5BX%5D_0%20%5Ctimes%20e%5E%7B-k%20%5Ctimes%20t%7D)
where,
: initial concentration of X
t: time elapsed
![\frac{[X]}{[X]_0}= e^{-k \times t}\\\frac{1/10[X]_0}{[X]_0}= e^{-0.028min^{-1} \times t}\\t=82min](https://tex.z-dn.net/?f=%5Cfrac%7B%5BX%5D%7D%7B%5BX%5D_0%7D%3D%20e%5E%7B-k%20%20%5Ctimes%20t%7D%5C%5C%5Cfrac%7B1%2F10%5BX%5D_0%7D%7B%5BX%5D_0%7D%3D%20e%5E%7B-0.028min%5E%7B-1%7D%20%20%5Ctimes%20t%7D%5C%5Ct%3D82min)
The earliest time Professor Utonium can come back to do experiments in the lab is:
4:00 + 82 = 5:22 am
Answer:
energy is being used to make or break bonds between molecules
Explanation:
if correct please consider brainliest
Loses one electron and becomes a positively <span>charged ion.
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