Answer:
1) titration
2) titrand
3) equivalence point
4) titrant
5) Burette
6) Indicator
Explanation:
The process of adding a known volume a standard solution to another solution to react with it in order to determine the concentration of the unknown solution is known as titration.
The solution to which another solution of known concentration is added is called the titrand while the solution of known concentration is called the titrant.
A burette is a glassware used to slowly add a known volume of the titrant to the titrand. An indicator shows the point when the reaction is complete by a color change. This is the point when the required amount of one solution has been added to the second solution. It is also called the equivalence point.
Answer:
load("tempdata.RData")
range(tempdata$temp)
## [1] 61.6 74.0
max(tempdata$year)
## [1] 2015
max(tempdata$temp)
## [1] 74
min(tempdata$temp)
## [1] 61.6
plot(tempdata$year, tempdata$temp, xlab = "Recorded Years of October", ylab = "Recorded Average Temperatures in Fahrenheit", main = "Average Recorded Temperature of October in Los Angeles")
model3 <- lm(tempdata$temp ~ tempdata$year, data = tempdata)
abline(model3, col = "red", lw = 3)
Explanation:
A) Jason is correct because smaller wings can cut through air better.
Answer:
/ Contactlist.java
import java.util.Scanner;
public class PhoneContacts
public static String GetPhoneNumber(String[] nameVec, String[] phoneNumberVec, String contactName, int arraySize) {
for (int i = 0; i < arraySize; i++) {
if (nameVec[i].equals(contactName)) {
return phoneNumberVec[i];
}
}
return "";
}
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int n = in.nextInt();
String[] names = new String[n];
String[] numbers = new String[n];
for (int i = 0; i < n; i++) {
names[i] = in.next();
numbers[i] = in.next();
}
System.out.println(GetPhoneNumber(names, numbers, in.next(), n));
}
}
Answer:
17.658 kPa
Explanation:
The hydrostatic pressure of a fluid is the weight of a column of that fluid divided by the base of that column.
Also, the weight of a column is its volume multiplied by it's density and the acceleration of gravity:
Meanwhile, the volume of a column is the area of the base multiplied by the height:
Replacing:
The base cancels out, so:
The pressure depends only on the height of the fluid column, the density of the fluid and the gravity.
If you have two point at different heights (or depths in the case of objects submerged in water) each point will have its own column of fluid exerting pressure on it. Since the density of the fluid and the acceleration of gravity are the same for both points (in the case of hydrostatics density is about constant for all points, it is not the case in the atmosphere), we can write:
We do not know at what depth the man of this problem is, but it doesn't matter, because we know the difference in height of the two points of interes (h1 - h2) = 1.8 m. So: