Answer:
For aluminum 110.53 C
For copper 110.32 C
Explanation:
Heat transmission through a plate (considering it as an infinite plate, as in omitting the effects at the borders) follows this equation:
Where
q: heat transferred
k: conduction coeficient
A: surface area
th: hot temperature
tc: cold temperature
d: thickness of the plate
Rearranging the terms:
d * q = k * A * (th - tc)
The surface area is:
If the pan is aluminum:
If the pan is copper:
The work done during the process is 359 btu
<u></u>
<u>Explanation:</u>
Given-
P1 = 15psia
P2 = 140 psia
V1 = 7ft³
a = 5 psia/ft³
b = C
P = aV +b
Work done, W = ?
P1 = aV1 + b
15 = 5 (7) + b
b = -20 psia
P2 = aV2 + b
140 = 5 ( V2) - 20
V2 = 32 ft³
The work done by the process is the area under the curve which is trapezoidal.
Therefore,
Work done, W = area of trapezoid
= (P2 + P1 / 2) (V2 - V1)
= ( 140 + 15 / 2 ) ( 32 - 7)
= 1937.5 psia ft³
= 1937.5/ 5.4039 = 359 btu
Therefore, the work done during the process is 359 btu
Answer:
363 pounds 32 degrees
Explanation:
Express your answers numerically in pounds and degrees to three significant figures separated by a comma. slader
