Answer:
15.625 watts
Explanation:
Recall that power is defined as the worked performed per unit of time:
Power = Work / time
The work done is Force * distance, so in our case the work is:
Work = 25 M * 5 m = 125 J
Then the power will be:
Power = 125 J / 8 sec = 15.625 watts
Answer:
2*10^9electrons
Explanation:
Remember that the net force will be zero at terminal voltege so
Mg = 6πrng
At 35v
We have
qvr = 6πrng
q= 6 x 3.142* nx 2.6*10^-5/35
q,= 3.2x 10^ - 10C
So using n= q/e
= 3.2x 10^ - 10C/1.6*10-19
= 2*10^9electrons
Answer:
Explanation:
Given
Two masses M and 2 M with velocity v in opposite direction
After collision they stick together
Initial momentum
final momentum
Conserving momentum
i.e. system moves towards the direction of 2M mass
Initial kinetic Energy 
Final Kinetic Energy 
loss of Energy
Answer: Graphing data is used to display data because it is easier to see trends in the data when it is displayed visually compared to when it is displayed numerically in a table.
