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Oduvanchick [21]

3 years ago

6

The force of gravity typically acts in a downward direction on the object on earth when an object is standing still, on the flat

ground ,in what direction does the support or normal force act?

1 answer:

Alja [10]3 years ago

5 0

The normal force acts to counter the gravitational force, that is the upward direction.

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What is the force when ur pulling heavy furniture that wont budge

elena55 [62]

Answer:

Gravity? is it multiple choice?

3 0

3 years ago

Read 2 more answers

A ball of moist clay falls 17.3 m to the ground. It is in contact with the ground for 24.0 ms before stopping. (a) What is the a

gizmo_the_mogwai [7]

Answer:

Acceleration, $767.08\ m/s^2$

Explanation:

Given that,

Height from a ball falls the ground, h = 17.3 m

It is in contact with the ground for 24.0 ms before stopping.

We need to find the average acceleration the ball during the time it is in contact with the ground.

Firstly, find the velocity when it reached the ground. So,

$v^2=u^2+2ah$

u = initial velocity=0 m/s

a = acceleration=g

$v=\sqrt{2gh} \\\\v=\sqrt{2\times 9.8\times 17.3} \\\\v=18.41\ m/s$

It is in negative direction, u = -18.41 m/s

Let a is average acceleration of the ball. Consider, v = and u = -18.41 m/s.

$a=\dfrac{v-u}{t}\\\\a=\dfrac{0-18.41}{24\times 10^{-3}}\\\\a=767.08\ m/s^2$

So, the average acceleration of the ball during the time it is in contact is $767.08\ m/s^2$ .

4 0

3 years ago

G a magnetic field perpendicular to the plane of a wire loop is uniform in space but changes with time t in the region of the lo

Luden [163]

Answer:

e = Δφ / Δt induced emf is proportional to enclosed flux

Also φ = B * A flux is proportional to area and enclosed field

If the induced emf e increases with time than the flux and hence the magnetic field is increasing with time (replace B with G)

Since e = ΔG * A / Δt if e is linear then G must also be linear and be proportional to the time

6 0

1 year ago

Select the correct answer. The motion of a car on a position-time graph is represented with a horizontal line. What does this in

enyata [817]

If the car's motion appears as a horizontal line on a <u><em>position-time </em></u>graph, it shows that as time changes, the car's position doesn't change.

This is just a complicated way to say that the car is <em>not moving</em>.<em> (A)</em>

7 0

3 years ago

A 3.50-m-long, 380kg steel uniform beam extends horizontally from the point where it has been bolted to the framework of a new b

LenKa [72]

Answer:

9064.44 Nm

Explanation:

Since the steel is uniform, the center of mass is also at the geometric center, which is 3.5 / 2 = 1.75 m from the bolted point.

Let g = 9.81 m/s2. The weight of the beam and the worker is

$W_b = m_bg = 380*9.81 = 3727.8 N$

$W_w = m_wg = 74*9.81 = 725.94N$

So the total torque about the bolted point is the sum of product of weights and distances from weight to the bolted point

$W_b*1.75 + W_w*2.4 = 3727.8 *1.75 + 725.94 * 3.5 = 9064.44 Nm$

8 0

3 years ago