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spin [16.1K]
2 years ago
14

Which of the following distinguishes the isotope uranium-238 from the isotope uranium-235?

Physics
2 answers:
WITCHER [35]2 years ago
8 0

Answer: A

Explanation:

Isotopes of different elements differ by the number of neutrons inside the nucleus.

Drupady [299]2 years ago
4 0
The answe is A- number of neutrons in the nucleus
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Light from a helium-neon laser (λ=633nm) passes through a circular aperture and is observed on a screen 5.80 mm behind the apert
Helga [31]

Explanation:

Whenever the light passes through hole or slit then it tends to bend that is actually a diffraction. It will then made the interference pattern of light and dark bands that due to constructive and destructive interference.

So by using the equation of diffraction,

dsinA = nL

SinA is a geometric component it can be written as,

d\frac{y}{x} = nL

∵ x is the distance from screen.

∵ y is the half of the width of central maximum.

now by putting the values in mm,

d\frac{17}{5.80} = 0.000633

d = 2.15×10^{-4} mm

7 0
3 years ago
A 1.0 × 10^3-kilogram car travels at a constant
laiz [17]
Centripetal acceleration can be calculated with the formula F=v^2/r

Substituting the values in, we get:

a=20^2/50
=8

Therefore the magnitude of the centripetal acceleration of the car is 8 ms^-2
6 0
3 years ago
What would happen if the compass were moved to the location of the black X
e-lub [12.9K]

Answer:

It is C

Explanation:

8 0
3 years ago
Read 2 more answers
A man with a weight of 550 N climbs a ladder to a height of 3.5m. How much work did he do?
Natasha2012 [34]

Answer: 1925 joules

Explanation:

weight of man = 550 N

height climbed = 3.5m

Work = ?

Since, work is done when the man pulled his weight over the height; work is expressed as the product of weight and height climbed

i.e Workdone = 550N x 3.5m

= 1925 joules

Thus, the man did a work of 1925 joules while climbing

7 0
4 years ago
An astronaut named Speedo takes a trip to Sirius, which is located a distance of 8 lightyears from the Earth. If the spaceship m
Softa [21]

Answer:

<em>a. 10 years</em>

<em>b. 6 years</em>

<em>c. 12 years behind</em>

<em></em>

Explanation:

speed of light c =  3x10^{8} m/s

distance of sirius from earth = 8 lightyears = 8 x c x 60 x 60 x 24 x 365 = 252288000c meters

speed of spaceship = 0.8c

time taken to reach sirius = distance covered divided by speed

t = d/s = 252288000c/0.8c = 315360000 sec

<em>1 year = 60 x 60 x 24 x 365 sec = 31536000 sec</em>

315360000 sec = 315360000/31536000 = <em>10 yrs</em>

<em>the time as observed by Goslo will be shorter than the real time as measured within the ship due to relativistic effects. using the relativistic relation for time dilation we have</em>

t' = t\sqrt{1 - \frac{v^{2} }{c^{2} } }

since v = 0.8c

v/c = 0.8

where t' is the relativistic time as observed by Goslo,

t is the time within the ship

t' = 10 x \sqrt{1 - 0.8^{2}  }  = <em>6 yrs</em>

<em></em>

If speedo turns around immediately after reaching  sirius, his total distance will be 252288000c x 2 = 50457600c meter

time taken = 50457600c/0.8 = 630720000 sec = 20 yrs

time within the ship will be calculated from time dilation

t' = t\sqrt{1 - \frac{v^{2} }{c^{2} } }

t' = 20 x  \sqrt{1 - 0.8^{2}  }  = 378432000 sec = <em>12 years behind</em>

4 0
3 years ago
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