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2 years ago

Types of isomers possible for ch3 ch2 ch2 ch3

Chemistry

1 answer:

puteri [66]2 years ago

4 0

Answer:

It has two isomers; n-butane and isobutane. Here n-butane is a straight-chain compound with four carbon atoms bonded with single covalent bonds. Explanation: Butane is an alkane with four carbon atoms so molecular formula is C4H10.

Explanation:

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You draw back on the piston of a pump and the volume of air in the pump doubles. Which of the following happens?

ohaa [14]

Answer: The correct answer is Option C.

Explanation:

We are given a piston of a pump, which means that there is no loss of the air. and there is a change in pressure and volume but temperature of the system remains constant.

As, the pressure of the system increases, there will be more number of particles. So, the number of collisions per unit area will increase.

$\text{Number of collisions}\propto \text{Pressure}$

But in the question, volume gets doubled. So, the pressure will be determined by using Boyle's Law:

$P\propto \frac{1}{V}$

$V_2\rightarrow 2V_1$

where, $V_1\text{ and }V_2$ are the initial and final volume respectively.

Putting the change in volume in above equation, we get:

$P_2=\frac{1}{2V_1}\\\\P_2=\frac{1}{2}P_1$

where, $P_1\text{ and }P_2$ are the initial and final pressure respectively.

As, the pressure is reduced to half of the initial pressure. So, the number of collisions per unit area will also be reduced to one-half.

Hence, the correct answer is Option C.

5 0

3 years ago

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Which of the following mixtures would result in a buffered solution when 1.0 L of each of the two solutions are mixed?

drek231 [11]

Answer:

c. 0.2 M HNO₃ and 0.4 M NaF .

Explanation:

A buffer is defined as the mixture of a weak acid with its conjugate base or a weak base with its conjugate acid.

A weak acid or weak base are defined as an acid or base that partially dissociates in aqueous solution. in contrast, a strong acid or base are acids or bases that is dissociated completely in water.

Thus:

a. 0,2M HNO₃ and 0.4 M NaNO₃. This is a mixture of a strong acid with its conjugate base. IS NOT a buffer.

b. 0.2 M HNO₃ and 0.4 M HF . This is a mixture of two strong acids. IS NOT a buffer.

c. 0.2 M HNO₃ and 0.4 M NaF . NaF is the conjugate base of a weak acid as HF is.

The reaction of HNO₃ with NaF is:

HNO₃ + NaF → HF + NaNO₃

That means that in solution you will have a weak acid (HF) with its conjugate base (NaF). Thus, this mixture IS a buffer.

d. 0.2 M HNO₃ and 0.4 M NaOH. This is the mixture of a strong acid with a strong base, thus, this IS NOT a buffer.

I hope it helps!

7 0

3 years ago

A gas occupying a volume of 656.0 mL at a pressure of 0.884 atm is allowed to expand at constant temperature until its pressure

7nadin3 [17]

Answer:

1.14 × 10³ mL

Explanation:

Step 1: Given data

Initial volume of the gas (V₁): 656.0 mL

Initial pressure of the gas (P₁): 0.884 atm

Final volume of the gas (V₂): ?

Final pressure of the gas (P₂): 0.510 atm

Step 2: Calculate the final volume of the gas

If we assume ideal behavior, we can calculate the final volume of the gas using Boyle's law.

P₁ × V₁ = P₂ × V₂

V₂ = P₁ × V₁/P₂

V₂ = 0.884 atm × 656.0 mL/0.510 atm = 1.14 × 10³ mL

5 0

3 years ago

It is widely known that fossil fuels pollute the environment and cause harmful effects. Why then are fossil fuels still being wi

stich3 [128]

Fossil fuels are still being widely used because of the fact that the demand for alternative fuels cannot be met by current manufacturers.

8 0

3 years ago

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Help please fast will mark as Brainliest

wlad13 [49]

Answer:

The answer is 2i on right hand side.

Explanation:

We should star by checking the equation from right.

First we check how many Zn r there in left hand side. Which is 1. Let us check how many Znr there in right hand side, there is 1.So Zn is balanced, and don't worry about Znplus2 on right hand side it is just the ions not how many zinc r there.

Now let us check how many I are there left hand side. Which is 2. Now how many I are there in right hand side? Only 1.

So we put 2 behind I.

Now there r 2 I on both sides.

Its simple actually.

3 0

3 years ago

Read 2 more answers