<u>Answer</u><u>:</u><u> </u>Rudolf Virchow
Answer:
Aluminum
Explanation:
Mass of 
= 1.68 g
Molar mass of = 143.32 g/mol
Thus,
From the reaction below:
3 moles of are produced when 1 mole of 
undergoes reaction.
So,
1 mole of are produced when 
mole of undergoes reaction.
0.01172 mole of are produced when 
mole of undergoes reaction.
Thus, moles of = 0.0039 moles
Let the atomic mass of X = x g/mol
atomic mass of chlorine = 35.5 g/mol
Thus, Molar mass of = x + 3(35.5) g/mol = x + 106.5 g/mol
Moles = 0.0039 moles
Mass = 0.521 g
Thus, molar mass = Given mass/ Moles = 0.521 / 0.0039 = 133.5897 g/mol
So,
x + 106.5 = 133.5897
x = 27.0897 g/mol
This Atomic weight corresponds to Aluminum. Hence, X is aluminum.
The heavy atom count of a casein molecule is 143 I believe
Answer:
104.84 moles
Explanation:
Given data:
Moles of Boron produced = ?
Mass of B₂O₃ = 3650 g
Solution:
Chemical equation:
6K + B₂O₃ → 3K₂O + 2B
Number of moles of B₂O₃:
Number of moles = mass/ molar mass
Number of moles = 3650 g/ 69.63 g/mol
Number of moles = 52.42 mol
Now we will compare the moles of B₂O₃ with B from balance chemical equation:
B₂O₃ : B
1 : 2
52.42 : 2×52.42 = 104.84
Thus from 3650 g of B₂O₃ 104.84 moles of boron will produced.
