Answer:
21.2 moles.
Explanation:
Hello!
In this case, for the given chemical reaction, we can see there is a 1:4 mole ratio between tetraphosphorous decaoxide and phosphorous; therefore, the following proportional factor provides the requested moles of phodphorous:
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Answer:
9.29 mol
Explanation:
Given data:
Number of moles = ?
Mass = 148.6 g
Solution:
Number of moles = mass/ molar mass
Molar mass of CH₄ = 16 g/mol
Now we will put the values in formula.
Number of moles = 148.6 g/ 16 g/mol
Number of moles = 9.29 mol
Thus 148.6 g have 9.29 moles.
Answer:
The equilibrium between the two forms of the gas is disturbed at high temperatures.
Answer:
Anode half reaction;
Co(s) ----> Co^2+(aq) + 2e
Cathode half reaction;
2Ag^+(aq) + 2e-------> 2Ag(s)
Explanation:
A voltaic cell is an electrochemical cell that spontaneously produces electrical energy from chemical reactions. A voltaic cell comprises of an anode (where oxidation occurs) and a cathode (where reduction occurs). The both electrodes are connected with a wire . A salt bridge ensures charge neutrality in the anode and cathode compartments. Electrons flow from anode to cathode.
For the cell referred to in the question;
Anode half reaction;
Co(s) ----> Co^2+(aq) + 2e
Cathode half reaction;
2Ag^+(aq) + 2e-------> 2Ag(s)
Explanation:
Rate law is defined as the rate of a reaction is directly proportional to the concentration of reactants at constant temperature.
![Rate \propto [\text{concentration of reactant}]^{n}](https://tex.z-dn.net/?f=Rate%20%5Cpropto%20%5B%5Ctext%7Bconcentration%20of%20reactant%7D%5D%5E%7Bn%7D)
= k ![[\text{concentration of reactant}]^{n}](https://tex.z-dn.net/?f=%5B%5Ctext%7Bconcentration%20of%20reactant%7D%5D%5E%7Bn%7D)
where, k = rate constant
n = order of reaction
For the given reaction, 
Hence, its rate will be as follows.
Rate = ![k[H_{2}][NO]](https://tex.z-dn.net/?f=k%5BH_%7B2%7D%5D%5BNO%5D)
Also, it is known that slowest step in a chemical reaction is the rate determining step.
Hence, for the given rate law correct reaction is as follows.
Step 1 : 
(slow)
Balancing this equation it becomes 
(slow)
Step 2: 
(fast)
