Answer:
The answer to your question is 8.2 g of TiF₄
Explanation:
Data
Theoretical yield = ?
mass of Ti = 5 g
mass of F₂ = 5 g
Balanced chemical reaction
Ti(s) + 2F₂ (g) ⇒ TiF₄(g)
Process
1.- Calculate the Molar mass of reactants and products
Ti = 48 g
2F₂ = 2( 19 x 2) = 76 g
TiF₄ = 48 + 76 = 124 g
2.- Calculate the limiting reactant
theoretical proportion Ti/F₂ = 48/76 = 0.63
experimental proportion Ti/F₂ = 5/5 = 1
Conclusion The limiting reactant is F₂ because the experimental proportion was lower than the theoretical proportion.
3.- Calculate the theoretical yield using the mass of F₂
76 g of F₂ --------------- 124 g of TiF₄
5 g of F₂ --------------- x
x = (5 x 124) / 76
x = 8.15 g of TiF₄
Answer:
A. 2.9*10^24
B. 3.4*10^21
C. 1.2*10^25
D. 1.7*10^23
Explanation:
1 mol of any particle has 6.02*10^23.
A. 4.8 mol Cu* 6.02*10^23 (1/mol) ≈2.9*10^24
B. 5.6x10^-3 mol C *6.02*10^23 (1/mol) ≈3.4*10^21
C. 20.0 mol Hg*6.02*10^23 (1/mol)≈1.2*10^25
D. 0.285 mol Na*6.02*10^23 (1/mol)≈1.7*10^23
Explanation:
<h2>Radium(Ra)=> </h2>
atomic number=88
<h2>BERYLLIUM (Be)=></h2>
atomic number =4
why is Ra larger than Be
<h3>1. since the atomic number of Ra is greater than Be, the number of electrons is more, which means there are more number of shells present in Ra than Be. </h3><h2>(atomic Radius)</h2>
<h2>2. the more the valence electron (excluding fully filled ones) the less is the nuclear attraction force</h2><h3>since Ra has more valence electron in its outermost shell, the nuclear attraction force is less which means that Ra 's size is greater than Be.</h3>
hope it helps:)
Answer: 0.176 atm
Explanation: Solution attached:
Use Boyle's Law to find the new pressure of the gas.
P1V1 = P2V2
Derive for P2
P2 = P1V1 / V2
= 5.5 atm ( 4.8 L ) / 150 L
= 0.176 atm
Answer:
Check the explanation
Explanation:
functional group found in the major organic product = alpha -beta unsaturated ketone
Reaction used to form this functional group = Michael condensation reaction
Also other reactions are - Aldol condensation , Robinson annulation reaction.
Kindly check the attached image below to see the step by step solution to the question above.
