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denis-greek [22]
4 years ago
10

How many atoms are in each elemental sample?

Chemistry
1 answer:
Gnesinka [82]4 years ago
3 0

Answer:

A. 2.9*10^24

B. 3.4*10^21

C. 1.2*10^25

D. 1.7*10^23

Explanation:

1 mol of any particle has 6.02*10^23.

A. 4.8 mol Cu* 6.02*10^23 (1/mol) ≈2.9*10^24

B. 5.6x10^-3 mol C *6.02*10^23 (1/mol) ≈3.4*10^21

C. 20.0 mol Hg*6.02*10^23 (1/mol)≈1.2*10^25

D. 0.285 mol Na*6.02*10^23 (1/mol)≈1.7*10^23

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The reaction N O space plus thin space O subscript 3 space rightwards arrow space N O subscript 2 space plus thin space O subscr
nikklg [1K]

Answer:

4.3 × 10⁻⁵ M s⁻¹

Explanation:

Step 1: Given data

  • Rate constant (k):  2.20 × 10⁷ M⁻¹s⁻¹
  • Concentration of NO ([NO]): 3.3 × 10⁻⁶ M
  • Concentration of O₃ ([O₃]): 5.9 × 10⁻⁷ M
  • First order with respect to both NO and O₃

Step 2: Write the balanced reaction

NO + O₃ ⇒ NO₂ + O₂

Step 3: Calculate the reaction rate

The rate law is:

rate = k × [NO] × [O₃]

rate = 2.20 × 10⁷ M⁻¹s⁻¹ × 3.3 × 10⁻⁶ M × 5.9 × 10⁻⁷ M

rate = 4.3 × 10⁻⁵ M s⁻¹

6 0
4 years ago
What is the basic building block of matter
nasty-shy [4]

Answer:

Atoms

Explanation:

Atoms are widely believed to be the most fundamental particle of matter and their basic building blocks. When atoms combines together, they form compounds. Molecules are another units of matter that are made up of tiny particles of atoms.

5 0
4 years ago
HELPP ASAP ITS FOR A TEST !!!
zepelin [54]

Answer:

Acid seeps into the ground and dissolves rock such as Limestone

Explanation:

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4 0
3 years ago
Read 2 more answers
How many chlorine molecules are in 7.02 l of chlorine gas at stp?
emmasim [6.3K]
The answer is:  [B]:  1.89 * 10²³  .
____________________________________________________

PV = nRT ;  is the equation for "STP" conditions; that is, the "ideal gas equation" .
_______________________________________________
                      i.e. when Pressure, "P" = 1.00 atm; 
                                    Temperature, "T" = 273 K;
_____________________________________ 
                           R = the ideal gas constant = ((0.08206 L-atm/K-mol)
                           n = number of moles;
___________________________________
So, we plug in our known values:
______________________________________________
<span>(1.00atm) (7.02L) = ("n" mol) (0.08206 L-atm/K-mol) (273K); </span>
<span>_____________________________________________
</span>→ 7.02 L·atm = (? mol) (22.4 L·<span>atm/mol) .
</span>
     (Note that t<span>he Molar Volume of a gas at STP is a constant using Avogadro's value of </span>22.4 L / mol.  1 mol of any ideal gas at STP occupies 22.4 L. An ideal gas takes the shape of its container)..
<span>_______________________________________________________
</span> → Divide EACH side of the equation by "(22.4 L·atm/mol)" ; 
________________________________________________
→ 7.02 L·atm / = ("n" mol) (22.4 L·atm/mol) ;
_________________________________________________
→ 7.02 L·atm / (22.4 L·atm/mol) =
                     [("n"  mol) (22.4 L·atm/mol)]/(22.4 L·atm/mol);
______________________________________________________  
<span>to get:  
_________________________________________________
 </span>→ n = <span>0.313 mol ;
</span>_____________________________________________________
Note: 1 mole = 1 mol = 6.022 * 10²³  molecules.
____________________________________________
  → So, 0.313 mol Cl₂ (g) molecules * [(6.022 * 10²³  molecules) / (1 mol)] =
___________________________________________________________
  → [(0.313) * (6.022 *10²³) ] molecules of Cl₂ (g) ;
___________________________________________________________
            →  =  1.88 * 10²³ molecules of Cl₂ g ; 
___________________________________________________________
                   → which most closely corresponds with answer choice:
___________________________________________________________ 
                                                       [B]:  1.89 * 10²³  . 
___________________________________________________________  
5 0
4 years ago
If 0.4506 g of KHP standard were titrated with NaOH and the endpoint was reached at 27.96 mL, what is the concentration (molarit
Lemur [1.5K]
Answer is in attachment.

Enjoy :)

6 0
3 years ago
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