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a_sh-v [17]
3 years ago
12

True or false the refraction of a wave is how many wavelengths pass a fixed point each second

Physics
2 answers:
Ksenya-84 [330]3 years ago
8 0
False. That description fits the wave's 'frequency'. 
It has nothing to do with refraction.
professor190 [17]3 years ago
6 0

Answer:

False

Explanation:

- Refraction is the phenomenon that occurs when a light wave crosses the interface between two different mediums. Because of the different index of refraction of the two mediums (also called optical density), the speed of light in the two mediums is different, so the light changes direction.

- The definition described in the text of this problem, instead, is the definition of frequency. In fact, frequency of a wave is defined as the number of complete cycles (or of complete wavelengths) that pass a fixed point each second.

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the answer is Titan
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2 years ago
NEED HELP NOW. I WILL BRAINLIEST
NeTakaya

Answer:

number of Protons=16

number of Neutrons=16

number of electrons=32

Explanation:

Tip:-

<em><u>Always the number of protons = the number of neutrons.</u></em>

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2 years ago
The magnetic field of an electromagnetic wave in a vacuum is Bz =(2.4μT)sin((1.05×107)x−ωt), where x is in m and t is in s. You
tatiyna

Answer:

Explanation:

Given

B_z=(2.4\mu T)\sin (1.05\times 10^7x-\omega t)

Em wave is in the form of

B=B_0\sin (kx-\omega t)

where \omega =frequency\ of\ oscillation

k=wave\ constant

B_0=Maximum\ value\ of\ Magnetic\ Field

Wave constant for EM wave k is

k=1.05\times 10^7 m^{-1}

Wavelength of wave \lambda =\frac{2\pi }{k}

\lambda =\frac{2\pi }{1.05\times 10^7}

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3 years ago
You have a length of tubing that is closed at one end. You cut the tubing into two pieces of unequal length, giving you a tube o
umka21 [38]

Answer:

The funda mental frequency of the original tube is 182Hz.

Explanation:

See the attachment for the calculation steps.

In order to calculate the fundamental frequency of the original closed tube we need to find the length of the tube which is equal to the sum of the lengths of the two new tubes.

For closed tubes

f = nv/4L (n = 1, 3, 5,...n)

f = nv/2L (n = 1, 2, 3,...n)

The details of calculation can be found below in the attachment.

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Read 2 more answers
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