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3 years ago

If a light wave is reflected with a 27° angle of reflection, what was the angle of incidence of which it was transmitted?

Physics

1 answer:

Leni [432]3 years ago

8 0

Answer:

it is 27 degree.

Explanation:

because angle of reflection is equal to angle of Inc dence

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If you had 8 balls and 7 of them were a certain weight, and 1 of them was heavier, how could you find the heaviest ball. All the

dybincka [34]

Answer:

There are two method of comparing the balls 1) using a balance 2) by only 2 weighings.

Explanation:

There are two method of comparing the balls 1) using a balance 2) by only 2 weighings.

Make the following groups - --- (1,2,3),(4,5,6),(7,8)

Step 1. compare the Weigh (1,2,3) and (4,5,6)

there are 2 possible outcomes:

1---both the group are of same weight. and named as (Case A)

2--- one of the group is heavier than other and named as (Case B)

Step 2. Let examine both case

In Case A --in this case, now compare the weight of 7th and 8th ball. By this you have recognize the heavier ball by 2 weighing method.

In Case B -- considered the heaviest group (assume group (1,2,3) is heavy), from this group take randomly two ball and compare the their weight. out of these two ball, one is heavy else the third ball is.

7 0

4 years ago

What must be the diameter of a cylindrical 120-m long metal wire if its resistance is to be 6.0 ω? the resistivity of this metal

Free_Kalibri [48]

The resistance of the cylindrical wire is $R=\frac{\rho l}{A}$ .

Here $R$ is the resistance, $l$ is the length of the wire and $A$ is the area of cross section. Since the wire is cylindrical $A=\frac{\pi d^2}{4}$ . Rearranging the above equation,

$A=\frac{\rho l}{R}\\ \frac{\pi d^2}{4}=\frac{\rho l}{R}\\ d=\sqrt{\frac{4\rho l}{\pi R}}$

Here $l=120, R=6, \rho=1.68(10^{-8})$ .

Substituting numerical values,

$d=\sqrt{\frac{4(1.68)(10^{-8}) (120)}{\pi (6)}}\\ d=0.0006541$

Te diameter of the wire is $0.6541 mm$

7 0

4 years ago

A heating element has a resistance of 180 Ω and draws a current of 1.60 A. What is its power?

iragen [17]

its either 288Watts or 112.5 Watts

5 0

3 years ago

Read 2 more answers

Tool used to measure time

charle [14.2K]

Answer:

clock

Explanation:

personal experience

6 0

3 years ago

Read 2 more answers

Two long conducting cylindrical shells are coaxial and have radii of 20 mm and 80 mm. The electric potential of the inner conduc

romanna [79]

Answer:

a) The speed of the electron as it reaches the inner conductor is closest to:

v = 1.45 × 10⁷m/s

b) The electric field magnitude between the cylinders is

E = 10,000V/m

Explanation:

given

inner radius of the cylinder r₁ = 20mm = 0.02m

outter radius of the cylinder r₂ = 80mm = 0.08m

potential difference V= 600V

mass of electron = 9.1×10⁻³¹kg

charge on electron = 1.6×10⁻¹⁹C

calculating the work done in bringing electron at inner conductor is

$W =\frac{1}{2}mv^{2}$

note:

$V = \frac{W}{q}$

∴W = (ΔV)q

(ΔV)q = $\frac{1}{2}mv^{2}$

(600)1.6×10⁻¹⁹ = ¹/₂ × 9.1×10⁻³¹ × v²

v² ≈ 2.11 × 10¹⁴

v = 1.45 × 10⁷m/s

According to the energy conservation law, the total energy of an isolated system is always constant.

The energy of an isolated system can neither be created nor be destroyed, it can only convert one form to another form.

∴ the maximum electric field

E = ΔV/d

E = 600/d

where d is the distance between the two points

where d = 0.06m

E = 600/0.06

E = 10,000V/m

Note: the electric field due to the potential difference between to points depends upon the potential difference V and the distance between both points d.

5 0

4 years ago