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3 years ago

Jenna flips two pennies 105 times how many times can she expect those coins to come up heads

1 answer:

7 0

The more observations you make the closer and closer the experimental probability will approach the theoretical probability. In this case the theoretical probability is:

P(HH)=(1/2)(1/2)=1/4

So in 105 trials one would expect to get two heads:

105(1/4)=26.25 times.

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Find the amount of sap the maple syrup producer collected from each tree if the total amount (5 gallons) was redistributed equal

Afina-wow [57]

The picture in the attached figure

we know that
total amount of sap =[3*(1/4)+2*(3/8)+4*(5/8)+1*(1)]
total amount of sap =[(3/4)+(6/8)+(20/8)+(1)]
total amount of sap =[(3/4)+(3/4)+(10/4)+(4/4)]
total amount of sap =[20/4]
total amount of sap =5 gallons
total of trees=10

[amount of sap collected from each tree]=total amount of sap/total of trees

[amount of sap collected from each tree]=5/10----> 0.5 gallons per tree

the answer is
0.5 gallons

7 0

3 years ago

Read 2 more answers

How to solve -8+squre root (5a-5)=-3

sertanlavr [38]

Answer:

$a=6$

Step-by-step explanation:

Given equation:

$-8+\sqrt{5a-5}=-3$

Solving for unknown variable $a$

Adding 8 both sides by additive property of equality.

$+8-8+\sqrt{5a-5}=-3+8$

$\sqrt{5a-5}=5$

Squaring both sides to remove the square root.

$(\sqrt{5a-5})^2=5^2$

$5a-5=25$

Adding 5 both sides by additive property of equality.

$5a-5+5=25+5$

$5a=30$

Dividing both sides by 6 to isolate $a$

$\frac{5a}{5}=\frac{30}{5}$

∴ $a=6$

8 0

3 years ago

Please help me with the answer!! There is the picture of the problem^

Gnoma [55]

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Please help me with this i need this grade

Wittaler [7]

Answer: B/The second answer

Step-by-step explanation:

5 0

3 years ago

The mean percentange of a population of people eating out at least once a week is 57℅

Sidana [21]

Answer:

The correct answer is B. between 56.45% and 57.55%

Complete statement and question:

The mean percentage of a population of people eating out at least once a week is 57% with a standard deviation of 3.50%. Assume that a sample size of 40 people was surveyed from the population a significant number of times. In which interval will 68% of the sample means occur?

between 55.89% and 58.11%

between 56.45% and 57.55%

between 56.54% and 57.46%

between 56.07% and 57.93%

Source: brainly.com/question/1068489

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Mean percentage of a population of people eating out at least once a week = 57%

Standard deviation = 3.5%

Sample size = 40

Confidence level = 68%

2. In which interval will 68% of the sample means occur?

For answering this question, we should find out the standard deviation of the sample, using this formula:

Standard deviation of the sample = Standard deviation of the population/√Sample size

Standard deviation of the sample = 3.5/√40

Standard deviation of the sample = 3.5/6.32

Standard deviation of the sample = 0.55

Let's recall that a confidence level of 68% means that 68% of the sample data would have a value between the mean - 1 time the standard deviation of the sample and the mean + 1 time the standard deviation of the sample. Thus:

57 - 1 * 0.55 = 57 - 0.55 = 56.45

57 + 1 * 0.55 = 57 + 0.55 = 57.55

The correct answer is B. between 56.45% and 57.55%

7 0

3 years ago