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Elanso [62]
2 years ago
13

1. What type of wave is sound? Does sound need a medium (substance) to travel through?

Physics
1 answer:
denpristay [2]2 years ago
6 0

Answer:

1. What type of wave is sound?

2.Does sound need a medium to travel through?

3. What are the properties of sound waves?

Explanation:

1. The type of waves sound are is mechanical waves.


2. Sound needs a solid, liquid or gas (material medium) to travel through.


3. I believe they are wavelength, amplitude, frequency, time period and velocity. 


I apologize if it is incorrect-

I hope it helps! Have a great day!

Anygays-

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The map of the world is overlaid with the boundaries of the tectonic plates. Look at the location marked with an asterisk (*). W
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3 years ago
What is the change in electric potential energy when the dipole moment of a molecule changes its orientation with respect to e⃗
AleksandrR [38]

Electric potential energy of a dipole is given as

U = - P.E

U = - PE cos\theta

so change in the potential energy is given by

U_f - U_i = (-PEcos\theta_2)- (-PEcos\theta_1)

\Delta U = PE (cos\theta_1 - cos\theta_2)

here initially it was parallel to electric field while finally it is perpendicular to the electric field

so we have

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8 0
3 years ago
Carbon dioxide (CO2) gas in a piston-cylinder assembly undergoes three processes in series that begin and end at the same state
topjm [15]

Answer:

a) W =400 kJ

b) W = 0 kJ

c) W =-160.944 KJ

Explanation:

<u>Given  </u>

<u><em>Process 1 ---> 2 </em></u>

The relation of the process P = constant

Pressure of point (1) P1 =  10 bar = P2

Volume of point (1) V1   = 1 m^3

Volume of point (2) V2 =4 m^3

The relation of the process V = constant  

<u>Process 2 ---> 3 </u>

The relation of the process V = constant

V3 = V2

Pressure of point (3) P3 = 10 bar

Volume of point (3) V3 = 4 m^3

<u>Process 3 ---> 1 </u>

The relation of the process PV = constant  

<u>Required  </u>

Sketch the processes on the PV coordinates

The work for each process in kJ  

<u>Solution  </u>

The work is defined by  

W=\int\limits^a_b {x} \, dx

<em>a=V2</em>

<em>b=V1</em>

<em>x=P</em>

<em>dx=dV</em>

<u>Process 1 ---> 2  </u>

P3 = P4 = 5 bar  

W=\int\limits^a_b {x} \, dx

<em>a=V3</em>

<em>b=V2</em>

<em>x=4</em>

<em>dx=dV</em>

putting the value of a, b, x, dx in above integral

W=400 kJ

<u>Process 2 ---> 3 </u>

V = constant Then there is no change in the volume,hence W = 0 kJ  

<u>Process 3 ---> 1  </u>

By substituting with point (1) --> 5 x .2 = C ---> C = 1 P = 5V^-1  

 W=\int\limits^a_b {x} \, dx

a=V1

b=V3

x=1V^-1

dx=dV

putting the value of a, b, x, dx in above integral

W=| ln V | limit a and b

  = -160.944 KJ

5 0
3 years ago
Why are electromagnets more useful than permanent magnets in many
Likurg_2 [28]

Answer: Electromagnets can be turned on and off by controlling the current

Explanation:

5 0
3 years ago
Read 2 more answers
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