(Q022) A negative magnetic anomaly a. occurs when the Earth's magnetic field measured in ancient rocks is the same as it is toda
1 answer:
You might be interested in
Answer:
(a) λ = 0.496 um (b) S =2π Δ d sinθ/ λ (c) I =gI₀ (d) For the central diffraction peak, a total of 5 interference maxima are present or available.
Note: find an attached copy of a part of the solution to the given question below.
Explanation:
Solution
Recall that:
d = 6.6 um
λ₀ =d/10
λ₀ = 6.6 um
Now,
(a) We find the wavelength λ of the light in water.
Thus,
λ water = (λ₀ )/n
= 0.66/1.33
So,
λ water = λ = 0.496 um
(b) We find the phase difference between the waves from slit 1 and 2
Now,
if a <<d and a<<λ
Then the path difference between the rays will be
Δ S₂N = Δ d sinθ
Thus, the phase difference becomes,
S = 2π Δ/λ is S= 2π Δ d sinθ/ λ
<u>(</u>c) The next step is to derive an expression for the intensity I as function of O and other relevant parameters.
Now,
Let p be the point where these two rays interfere with each other.
Thus,
The electric field vector coming out from slot and and slot 2 is
E₁= E₀₁ cos (ks₁ p - wt) i
E₂ = E₀₂ cos (ks₂ p - wt) i
Note: Kindly find an attached copy of a part of the solution to the given question below.
Answer:
The ball travels <u>1.31 m horizontally</u> before hitting the ground.
Explanation:
Given:
Initial velocity of the ball is,
Angle of projection is,
Initial height of the ball is,
Final height of the ball is,
Now, horizontal and vertical components of initial velocity are given as:
Plug in the given values and find . This gives,
Now, there is acceleration due to gravity acting in the vertical direction. The direction is downward. So, .
Now, using equation of motion in the vertical direction, we have:
Plug in the given values and solve for time 't'. This gives,
On solving the above quadratic equation, we get:
Ignoring the negative result as time can't be negative. So, time taken by the ball to reach the ground is 0.57 s.
Now, as the ball moves, there is no force acting on it in the horizontal direction. So, the acceleration in the horizontal direction is 0.
Now, we know that, when acceleration is zero, the body moves with a constant speed.
Hence, distance traveled in the horizontal direction is given as:
Horizontal distance = Horizontal component of initial velocity × Time
Plug in the given values and solve for 'R'. This gives,
So, the ball travels 1.31 m horizontally before hitting the ground.