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a_sh-v [17]
2 years ago
8

Five the equation of line that is perpendicular to f(x)=-2x+1 that goes through point (0,5)

Mathematics
1 answer:
Alinara [238K]2 years ago
7 0

Answer:

y = \frac{1}{2} x + 5

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

f(x) = - 2x + 1 ← is in slope- intercept form

with slope m = - 2

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{-2} = \frac{1}{2} , then

y = \frac{1}{2} x + c

the line crosses the y- axis at (0, 5 ) ⇒ c = 5

y = \frac{1}{2} x + 5 ← equation of perpendicular line

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Graph the following inequality and then select the correct graph below. y ≥ 3x - 3
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Answer:

Given the inequality: y\geq 3x-3

The related equation for the given equation is:

y = 3x -3                ......[1]

x -intercepts: The point where the line crosses the x-axis

Substitute the value of y= 0 in [1] to solve for x;

0 = 3x -3

Add both sides 3 we get;

0 + 3 = 3x -3 +3

Simplify:

3 = 3x

Divide both sides by 3 we get;

\frac{3}{3} = \frac{3x}{3}

Simplify:

1 = x

or x = 1

x-intercept is (1 , 0)

y-intercepts: The point where the line crosses the y-axis

Substitute the value of x= 0 in [1] to solve for y;

y =3(0) -3 = 0-3

Simplify:

y = -3

y-intercept = (0 , -3)

When your inequality symbol:

  • Greater than (>)  or Greater than or equal to (\geq), then the solution region is above the boundary line.
  • Less than (<) or Less than or equal to(\leq), then your solution region is below the boundary line.

Also,  when the symbol is:

"> , < ,  then we draw a dashed line,

"\leq , \geq",  then we draw a solid line.

Since, the given inequality i.e  y\geq 3x-3  symbol is "\geq" , draw a solid line and shade above the line:

As you can see the given inequality graph below in the attachment

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