Question

Five the equation of line that is perpendicular to f(x)=-2x+1 that goes through point (0,5)

Answer 1

Answer:

y = $\frac{1}{2}$ x + 5

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

f(x) = - 2x + 1 ← is in slope- intercept form

with slope m = - 2

Given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{-2}$ = $\frac{1}{2}$ , then

y = $\frac{1}{2}$ x + c

the line crosses the y- axis at (0, 5 ) ⇒ c = 5

y = $\frac{1}{2}$ x + 5 ← equation of perpendicular line