Answer:
The fifth degree Taylor polynomial of g(x) is increasing around x=-1
Step-by-step explanation:
Yes, you can do the derivative of the fifth degree Taylor polynomial, but notice that its derivative evaluated at x =-1 will give zero for all its terms except for the one of first order, so the calculation becomes simple:
and when you do its derivative:
1) the constant term renders zero,
2) the following term (term of order 1, the linear term) renders: 
since the derivative of (x+1) is one,
3) all other terms will keep at least one factor (x+1) in their derivative, and this evaluated at x = -1 will render zero
Therefore, the only term that would give you something different from zero once evaluated at x = -1 is the derivative of that linear term. and that only non-zero term is: 
as per the information given. Therefore, the function has derivative larger than zero, then it is increasing in the vicinity of x = -1
I think it will be B 610 and 820 but im not sure.
Hope This Helps!
~Cupcake
$820.02
Step-by-step explanation:
Since the Taylor family had cash receipts of $876.16 and their excess of cash receipts above cash payments was $56.14.
The total cash payments for the month will be calculated as:
= $876.16 - $56.14
= $820.02
Answer:
458 turns/min ----- 13740/30 min
Step-by-step explanation:
3206/7 (min) = 458
458 x 30 (min) = 13740
Answer:
a = 5
Remainder when p(x) is divided by x+2 = 62
Step-by-step explanation:
Given:
P(x) = x⁴-2x³+3x²-ax+3a-7
When x+1 divides the polynomial p(x) the ramainder is 19.
Applying remainder theorem,
x = -1
p(-1) = 19
Substitute the x = -1 into the polynomial expression
p(-1) = (-1)⁴-2(-1)³+3(-1)²-a(-1)+3a-7 = 19
1+2+3+a+3a-7 = 19
6-7+4a = 19
4a-1 = 19
4a = 19+1
4a = 20
a = 20/4
a = 5.
Hence, a = 5
p(x) = x⁴-2x³+3x²-5x+8
If p(x) is divided by x+2,
Then the remainder is p(-2)
p(-2) = (-2)⁴-2(-2)³+3(-2)²-5(-2)+8
p(-2) = 16+16+12+10+8
p(-2) = 62
Hence the remaider when p(x) is divided by x+2 is 62
