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lesya [120]
3 years ago
10

70 kg to mg i need to show the work of how i did it

Physics
1 answer:
lyudmila [28]3 years ago
4 0

Answer:

70000000 mg

Explanation:

1 gram (kg) is equal to 1000000 milligrams (mg).

1 kg = 106 mg = 1000000 m

7 kg × 1000000

= 7000000 mg

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A 55 kg skater spins 12 m/s while carving a circle on the ice that has a radius of 6.0m. What net force must act on the skater t
vivado [14]
F = m.a
a = v^2 / r
a = 12^2 / 6.0
a = 24 m/s^2
F = 55 × 24
F = 1320 N
4 0
3 years ago
An 85.0-kg mountain climber plans to swing down, starting from rest, from a ledge using a light rope 6.50 m long. he holds one e
Rainbow [258]

Understanding the given:
85 kg mountain climber
6.50 m long rope
gravity = 10m/s2

If we want to identify the work done on this scenario 
we get f = 85kg x 10m/s2 = 850 N
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4 0
3 years ago
If the primary of a transformer were connected to a dc power source,
QveST [7]

Answer:

D. only briefly while being connected or disconnected.

Explanation:

As we know that transformer works on the principle of mutual inductance

here we know that as per the principle of mutual inductance when flux linked with the primary coil charges then it will induce EMF in secondary coil

So here when AC source is connected with primary coil then it will give output across secondary coil because AC source will have change in flux with time.

Now when we connect DC source across primary coil then it will not induce any EMF across secondary coil because DC source is a constant voltage source in which flux will remain constant always

So here in DC source the EMF will only induce at the time of connection or disconnection when flux will change in it while rest of the time it will give ZERO output

so correct answer will be

D. only briefly while being connected or disconnected.

8 0
3 years ago
What will happen to force?
telo118 [61]

Answer:

it will double because im right

8 0
3 years ago
A 100-kg running back runs at 5 m/s into a stationary linebacker. It takes 0.5 s for the running back to be completely stopped.
Elza [17]

Answer:

1000 N

Explanation:

First, we need to find the deceleration of the running back, which is given by:

a=\frac{v-u}{t}

where

v = 0 is his final velocity

u = 5 m/s is his initial velocity

t = 0.5 s is the time taken

Substituting, we have

a=\frac{0-5 m/s}{0.5 s}=-10 m/s^2

And now we can calculate the force exerted on the running back, by using Newton's second law:

F=ma=(100 kg)(-10 m/s^2)=-1000 N

so, the magnitude of the force is 1000 N.

6 0
3 years ago
Read 2 more answers
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