<h2>When two object P and Q are supplied with the same quantity of heat, the temperature change in P is observed to be twice that of Q. The mass of P is half that of Q. The ratio of the specific heat capacity of P to Q</h2>
Explanation:
Specific heat capacity
It is defined as amount of heat required to raise the temperature of a substance by one degree celsius .
It is given as :
Heat absorbed = mass of substance x specific heat capacity x rise in temperature
or ,
Q= m x c x t
In above question , it is given :
For Q
mass of Q = m
Temperature changed =T₂/2
Heat supplied = x
Q= mc t
or
X=m x C₁ X T₁
or, X =m x C₁ x T₂/2
or, C₁=X x 2 /m x T₂ (equation 1 )
For another quantity : P
mass of P =m/2
Temperature= T₂
Heat supplied is same that is : X
so, X= m/2 x C₂ x T₂
or, C₂=2X/m. T₂ (equation 2 )
Now taking ratio of C₂ to c₁, We have
C₂/C₁= 2X /m.T₂ /2X /m.T₂
so, C₂/C₁= 1/1
so, the ratio is 1: 1
Answer:
Explanation:
a.
b. R3= 1/2R2=6 ôm
R12= R1+R2=20 ôm
Rtđ=R12.R3/R12+R3= 4,62 ôm
c. U= I.Rtđ = 2.4,62=9,23 V
I1=I2= 9,23/20= 0,4615 A
I3= 2-0,4615=1,5385 A
The atomic number of Na is 11
Thus it’s electronic configuration is 2,8,1
It’s valency is 1.
Thus it will loose an electron to form a stable compound with a completely filled outermost shell.
Na looses 1 electron
Answer:
Because the wavelengths of macroscopic objects are too short for them to be detectable.
Explanation:
Wavelength of an object is given by de Broglie wavelength as:
Where, 'h' is Planck's constant, 'm' is mass of object and 'v' is its velocity.
So, for macroscopic objects, the mass is very large compared to microscopic objects. As we can observe from the above formula, there is an inverse relationship between the mass and wavelength of the object.
So, for vary larger masses, the wavelength would be too short and one will find it undetectable. Therefore, we don't observe wave properties in macroscopic objects.
Answer:
A) energy to be stored = 354.4J
B) capacitance = 0.0454 farad
Explanation:
Detailed explanation and calculation is shown in the image below
