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2 years ago

11

How much time does it take for a rattlesnake to strike its victim if it is strikes at a speed of 1.25 m/s and the victim is exac

tly 5 meters away?

1 answer:

Marianna [84]2 years ago

6 0

Answer:

4 seconds

Explanation:

5/1.25=4

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A. If the rock weighs 1050 N, how far does the girl move her end of the lever if the lever is

3241004551 [841]

student is removing rocks from a garden. She exerts a force of 218 N on a lever to raise one rock a distance of 11.0 cm.

Answer:

52.98 cm

Explanation:

The ratio of forces and distance moved will be the same hence we apply cross multiplication rule

If 218 N can only raise the rock to a distance of 11 cm then we check the distance it can move when force is increased to 1050 N

218 N=11 cm

1050 N=?

By cross multiplication, the distance will be equivalent to $\frac {1050\times 11 cm}{218}=52.981651376146\ cm\approx 52.98\ cm$

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3 years ago

What muscle are controlled by the autonomic muscle system and are involuntary

FromTheMoon [43]

The answer is smooth muscle, Hope this helped! Have a good day!

4 0

3 years ago

Read 2 more answers

What force is affected when the distance between two objects remains the same and the mass of each object is doubled?.

rusak2 [61]

Answer:

Gravitational force between masses there is Gravitational force .

3 0

2 years ago

A block of density pb = 9.50 times 10^2 kg/m^3 floats face down in a fluid of density pt = 1.30 times 10^3 kg/m^3. The block has

Nookie1986 [14]

Answer:

The depth and acceleration are 0.1919291 ft and 3.61 m/s².

Explanation:

Given that,

Density of block $\rho_{b} =9.50\times10^2\ kg/m^3$

Density of fluid $\rho_{t} =1.30\times10^3\ kg/m^3$

We need to calculate the depth

Using balance equation

$mg=\rho g V$ ....(I)

We know that,

The density is

$\rho=\dfrac{m}{V}$

$m=\rh0\times V$

Put the value of m in equation (I)

$\rho_{b}\times V\times g=\rho_{t}\times g\times V$

$\rho_{b}\times A\times H\times g=\rho_{t}\times g\times A\times h$

$h=\dfrac{\rho_{b}H}{\rho_{t}}$

Put the value into the formula

$h=\dfrac{9.50\times10^2\times8.00\times10^{-2}}{1.30\times10^3}$

$h= 5.85\ cm$

$h=0.1919291\ ft$

We need to calculate the acceleration

Using formula of net force

$F_{net}=\rho_{t}\times g\times V- \rho_{b}\times g\times V$

$ma=\rho_{t}\times g\times V- \rho_{b}\times g\times V$

$\rho_{b}\times V\times a=\rho_{t}\times g\times V- \rho_{b}\times g\times V$

$a=(\dfrac{\rho_{t}}{\rho_{b}}-1)g$ ....(II)

Put the value in the equation (II)

$a=(\dfrac{1.30\times10^3}{9.50\times10^2}-1)\times9.8$

$a=3.61\ m/s^2$

Hence, The depth and acceleration are 0.1919291 ft and 3.61 m/s².

4 0

3 years ago

Two positive charges of 6.0 x 10^-6 C are separated by 0.50 m. Calculate the force of electrical attraction

SpyIntel [72]

Answer:

Force between two charges is given as 1.296 N

Explanation:

As we know that the two charges will attract or repel each other when they are placed near to each other

Here we know that electrostatic force is given as

$F = \frac{kq_1 q_2}{r^2}$

here we have

$q_1 = q_2 = 6 \times 10^{-6} C$

distance between two charges is given as

r = 0.50 m

so we have

$F = \frac{(9\times 10^9)(6 \times 10^{-6})^2}{0.50^2}$

$F = 1.296 N$

3 0

3 years ago