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Aleks [24]
4 years ago
8

The local church is hosting a carnival which includes a bumper car ride. Bumper car A and its driver have a mass of 300 kg; bump

er car B and its driver have a mass of 200 kg. Bumper car A has a velocity to the right of 2 m/s and bumper car B is at rest. At t = 0 s, bumper car A and B are separated by 10 m. Bumper car A accelerates at 1 m/s2 to a velocity of 4 m/s and continues at this constant speed until colliding with bumper car B.
Calculate the time required for bumper car A to travel the 10 m to collide with bumper car B.
Calculate the speed of bumper car A following the collision with bumper car B, which now has a velocity to the right of 3 m/s.
Is the direction of motion for bumper car A following the collision with bumper car B to the right, to the left, or is bumper car A at rest?
Is the collision elastic? Justify your answer.
Physics
1 answer:
lukranit [14]4 years ago
8 0

Answer:

a. 20 s

b. 0 m/s  

c. right

d.no its inelastic because when the car b was at rest and a was coming in at it, since b had no force what so ever car a swept it away with it moving to the right

Explanation:

im not sure though

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The question is in the attachment. ​
sammy [17]

Answer:

Correct answer:  Yes, with acceleration a = 10 m/s²

Explanation:

By definition acceleration is equal.

a = ΔV / Δt = (V₂ - V₁) / (t₂ - t₁)

a = (10 - 0)/ (1 - 0) = (20 - 10)/ (2 - 1) = ........ (50 - 40)/ (5 -4) = 10 m/s²

a = 10 m/s²

God is with you!!!

5 0
4 years ago
2. A small car has a mass of 890 kg. What is its weight? (Hint: remember the definition of weight).
Dafna1 [17]

What is the weight? The weight of a 890 kg car is:

8727.9185 newtons

or

0.981057067 tons force

or

31393.8261 ounces force

Hope that helps! I apologize if it does not answer your question!

I used this site: <u><em>https://www.sensorsone.com/mass-to-weight-calculator/</em></u>

3 0
3 years ago
Four electrons are located at the corners of a square 10.0 nm on a side, with an alpha particle at its midpoint. How much work i
Elis [28]

Four electrons are placed at the corner of a square

So we will first find the electrostatic potential at the center of the square

So here it is given as

V = 4\frac{kQ}{r}

here

r = distance of corner of the square from it center

r = \frac{a}{\sqrt2}

r = \frac{10nm}{\sqrt2} = 7.07 nm

Q = e = -1.6 * 10^{-19} C

now the net potential is given as

V = \frac{4 * 9*10^9 * (-1.6 * 10^{-19})}{7.07 * 10^{-9}}

V = 0.815 V

now potential energy of alpha particle at this position

U_i = qV = 2*1.6 * 10^{-19} * (-0.815) = -2.6 * 10^{-19} J

Now at the mid point of one of the side

Electrostatic potential is given as

V = 2\frac{kQ}{r_1} + 2\frac{kQ}{r_2}

here we know that

r_1 = \frac{a}{2} = 5 nm

r_2 = \sqrt{(a/2)^2 + a^2} = \frac{\sqrt5 a}{2}

r_2 = 11.2 nm

now potential is given as

V = 2\frac{9 * 10^9 * (-1.6 * 10^{-19})}{5 * 10^{-9}} + 2\frac{9*10^9 * (-1.6 * 10^{-19})}{11.2 * 10^{-9}}

V = -0.576 - 0.257 = -0.833 V

now final potential energy is given as

U_f = q*V = 2*1.6 * 10^{-19}* (-0.833) = -2.67 * 10^{-19} J

Now work done in this process is given as

W = U_f - U_i

W = (-0.267 * 10^{-19}) - (-0.26 * 10^{-19}}

W = -7 * 10^{-22} J

8 0
3 years ago
Apart from physical factors, what other environmental factors are in your environment?
lora16 [44]

Answer:

Explanation:

Factors which affects and impacts our environment may include water, sunlight, buildings and so many other. The factors which can touched are called the physical factors. The physical factirs include buildings, humans and so on. Other factirs which aren't physical inckide the the effects posed to the environment t by biological and chemical factirs which may include, the impacts in sunlight and Rainfall, the pH and so on.

5 0
4 years ago
How does fertilizer run off pollution?
velikii [3]
When it rains, the growth aids in the soil drift 

5 0
3 years ago
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