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madreJ [45]
2 years ago
11

Find the slope of the line passing through the points , 2−6 and , −9−6

Mathematics
1 answer:
aalyn [17]2 years ago
4 0

I will assume that we are trying to find the slope between (2,-6) and (-9,-6)

The slope's equation ⇒  \frac{y2-y1}{x2-x1}

<u />

<u>Let's set the variables:</u>

    (x1, y1) --> (2, -6)

    (x2, y2) --> (-9, -6)

<u>Now let's plug them in:</u>

 Slope = \frac{-6--6}{-9-2} =\frac{0}{-11} =0

<u>Thus the slope of the line is 0</u>.

Hope that helps!

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A driver's education course compared 1,500 students who had not taken the course with 1,850 students who had. Of those students
aivan3 [116]

Answer:

P-value is less than 0.999995 .

Step-by-step explanation:

We are given that a driver's education course compared 1,500 students who had not taken the course with 1,850 students who had.

Null Hypothesis, H_0 : p_1 = p_2 {means students who took the driver's education course and those who didn't took have same chances to pass the written driver's exam the first time}

Alternate Hypothesis, H_1 : p_1 > p_2 {means students who took the driver's education course were more likely to pass the written driver's exam the first time}

The test statistics used here will be two sample Binomial statistics i.e.;

                             \frac{(\hat p_1 - \hat p_2)-(p_1 - p_2)}{\sqrt{\frac{\hat p_1(1- \hat p_1)}{n_1} + \frac{\hat p_2(1- \hat p_2)}{n_2} } } ~ N(0,1)

Here, \hat p_1 = No. of students passed the exam ÷ No.of Students that had taken the course

 \hat p_1  = \frac{1150}{1850}            Similarly,  \hat p_2 = \frac{1440}{1500}          n_1 = 1,850       n_2 = 1,500

  Test Statistics = \frac{(\frac{1150}{1850} -\frac{1440}{1500})-0}{\sqrt{\frac{\frac{1150}{1850}(1- \frac{1150}{1850})}{1850} + \frac{\frac{1440}{1500}(1- \frac{1440}{1500})}{1500} } } = -27.38

P-value is given by, P(Z > -27.38) = 1 - P(Z > 27.38)

Now, in z table the highest critical value given is 4.4172 which corresponds to the probability value of 0.0005%. Since our test statistics is way higher than this so we can only say that the p-value for an appropriate hypothesis test is less than 0.999995 .

6 0
3 years ago
Describe the accumulated value a of the sum of money P the principal after two years at annual percent rich are in the decimal f
elena-14-01-66 [18.8K]

In order to calculate the value of t, we can use the given formula with the values P = 6000, A = 2P and i = 11% = 0.11:

\begin{gathered} 2\cdot6000=6000\cdot e^{0.11t}\\ \\ 2=e^{0.11t}\\ \\ \ln2=\ln e^{0.11t}\\ \\ 0.693147=0.11t\\ \\ t=\frac{0.693147}{0.11}=6.3 \end{gathered}

Therefore the time needed is t = 6.3 years.

8 0
1 year ago
The relationship (3,2)(2,5) (8,5) (3,6) is a function<br> A True<br> B) False
Katyanochek1 [597]
The answer is true

Hope this helped!
7 0
3 years ago
500.000.000 written in scientific notation?​
Natali [406]

\large \mathfrak{Answer : }

Scientific notation for above vLue is :

  • 5 \times 10 {}^{8}

8 0
3 years ago
Pleasee help me guyss .
Setler79 [48]

Answer:

24%

Step-by-step explanation:

25 - 19 = 6

25 = 100%

2.5 = 10%

1.25 = 5%

0.25 = 1%

5 = 20%

1 = 4%

6 = 24%

Hope this helps :)

3 0
3 years ago
Read 2 more answers
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