12. The most common factors that cause chemical reactions to occur are all the following except

Copper(l) sulfide can react with oxygen to produce copper metal by the reaction cu2s + o2 => 2cu + so2. if 5.00 g of cu2s is

valentina_108 [34]

To answer this problem, we write first the stoichiometric equation. Thus we have,

Cu2S + O2 => 2Cu + SO2

Next, we check if the equation is balanced or not.

(left) (right)
2 Cu = 2 Cu
1 S = 1 S
2 O = 2 O

So the stoichiometric equation is balanced, let's proceed in solving the theoretical yield of Cu given 5 g of Cu2S.

First, we solve for Cu2S in moles,
5 g Cu2S x 1 mol Cu2S = 0.0314 mol Cu2S
159.16 g Cu2s

Secondly, convert moles of Cu2S to moles Cu. Note for every mole of Cu2S we get 2 moles of Cu. Thus,

0.0314 mo Cu2S x 2 mol Cu = 0.0628 mole Cu
 1 mol Cu2S

Lastly, we convert mole Cu to g Cu via multiplying by Cu's MW.

0.0628 mole Cu x 63.546 g Cu = 3.99 g Cu or 4 g Cu
 1 mole Cu

ANSWER: 4 g Cu

4 0

2 years ago

Read 2 more answers

Which element has the least metallic character among Li,Be,Na and Mg

dem82 [27]

The element that has the least is na

7 0

3 years ago

Who established atomic numbers as the basis for organizing the periodic table?

Jobisdone [24]

Answer:

Henry Moseley.

Explanation:

Hello,

Henry Moseley's work stated that it is better to organize the periodic table in the light of the atomic number (which accounts for the amount of protons and electrons) instead of the atomic mass, because atomic numbers are not arbitrarily assigned as long as they have the aforesaid physical basis.

Best regards.

3 0

2 years ago

How many grams of nano3 remain in solution at 20 ∘c?

Amanda [17]

the table say that at 20 degree celcius 88.0g of NANO3 will remain dissolved in 100 gm of H2O so at 20 degree celcius 80.0g of H20 will dissolve (88.0g)x(80g/100g)=70.4g of NANO3 so at 20 degree celcius 86.3g-70.4g= 15.9 gram of NANO3 will come out of solution.

8 0

2 years ago

Consider the neutralization reaction 2 HNO 3 ( aq ) + Ba ( OH ) 2 ( aq ) ⟶ 2 H 2 O ( l ) + Ba ( NO 3 ) 2 ( aq ) A 0.120 L sample

k0ka [10]

Answer:

The concentration of the HNO3 solution is 0.150 M

Explanation:

Step 1: Data given

Volume of the unknown HNO3 sample = 0.120 L

Volume of the 0.200 M Ba(OH)2 = 45.1 mL

Step 2: The balanced equation

2HNO3 + Ba(OH)2 ⟶ Ba(NO3)2 + 2H2O

Step 3: Calculate moles Ba(OH)2

moles Ba(OH)2 = molarity * volume

moles Ba(OH)2 = 0.200 M * 0.0451 L

moles Ba(OH)2 = 0.00902 moles

Step 4: Calculate moles of HNO3

For 1 mole of Ba(OH)2 we need 2 moles of HNO3

For 0.00902 moles of Ba(OH)2 we need 2*0.00902 = 0.01804 moles

Step 5: Calculate molarity of HNO3

molarity = moles / volume

molarity = 0.01804 / 0.120 L

Molarity = 0.150 M HNO3

The concentration of the HNO3 solution is 0.150 M

6 0

2 years ago