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katrin [286]
2 years ago
7

Hey guys i needed some help on this

Chemistry
1 answer:
Nostrana [21]2 years ago
4 0

Based on the bond energies given, the standard enthalpy of the reaction, ΔH°(rxn) is -296 kJ.

<h3>What is standard enthalpy change of a reaction?</h3>

The standard enthalpy change of a reaction is the energy changes involved when substances react under standard conditions to form products.

  • ΔH°(rxn) = sum of the bond energies of bonds being broken - sum of the bond energies of the bonds being formed.

The standard enthalpy of the reaction, ΔH°(rxn) is calculated as follows:

Sum of energy of bonds broken = 839 + (2 × 413) + (432 × 2) = 2529 kJ

Sum of energy of bonds formed = 347 + (6 × 413) = 2825 kJ

ΔH°(rxn) = (2529 - 2825) kJ

ΔH°(rxn) = -296 kJ

Therefore, the standard enthalpy of the reaction, ΔH°(rxn) is -296 kJ.

Learn more about standard enthalpy at:brainly.com/question/25758173

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Calculate the number of kilojoules of energy required to convert 50.0 grams of solid DMSO initially at a temperature of 19.0°C t
GuDViN [60]

Answer:

20.79 kilojoules

Explanation:

Using Q = m×c×∆T

Where;

Q = Quantity of heat (J)

c = specific heat capacity of solid DMSO (1.80 J/g°C)

m = mass of DMSO

∆T = change in temperature

According to the provided information, m= 50g, initial temperature = 19.0°C, final temperature= 250.0°C

Q = m×c×∆T

Q = 50 × 1.80 × (250°C - 19°C)

Q = 90 × 231

Q = 20790 Joules

To convert Joules to kilojoules, we divide by 1000 i.e.

20790/1000

= 20.79 kilojoules

Hence, 20.79 kilojoules of energy is required to convert 50.0 grams of solid DMSO to gas.

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3 years ago
I NEED THIS ASAP TODAY PLEASSSSEEEEEE
alukav5142 [94]

Option C, mass would be same. Only the gravitational pull will be different

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When it is water, what state is it solid, liquid or gas?
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ANSWER:

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4 years ago
There are three types of plate boundaries. Which choice is NOT a type of plate boundary?
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A sample of gas occupies 7.80 liters at 425=C2=B0C? What will be the volume= of the gas at 35=C2=B0C if the pressure does not ch
luda_lava [24]

To solve this we assume that the gas inside the balloon is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant pressure and number of moles of the gas the ratio T/V is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

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V2 = T2 x V1 / T1

V2 = 308.15 x 7.80 / 698.15

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7 0
3 years ago
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