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Harrizon [31]
2 years ago
13

What is the origin of fahrenheit and centigrade temperature scales?.

Chemistry
2 answers:
padilas [110]2 years ago
8 0

Answer:

The 18th-century German physicist Daniel Gabriel Fahrenheit originally took as the zero of his scale the temperature of an equal ice-salt mixture

Explanation:

Zepler [3.9K]2 years ago
5 0

Answer:

Explanation:

The 18th-century German physicist Daniel Gabriel Fahrenheit originally took as the zero of his scale the temperature of an equal ice-salt mixture

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What is the electron configuration for<br> 08<br> 16
Elis [28]

The electron configuration for Oxygen : [He] 2s²2p⁴

<h3>Further explanation</h3>

Writing electron configurations starts from the lowest to the highest sub-shell energy level. There are 4 sub-shells in the shell of an atom, namely s, p, d, and f. The maximum number of electrons for each sub-shell is  

• s: 2 electrons  

• p: 6 electrons  

• d: 10 electrons and  

• f: 14 electrons  

Charging electrons in the sub-shell uses the following sequence:  

<em>1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁶, 5s², 4d¹⁰, 5p⁶, 6s², etc.  </em>

The element is Oxgen, with symbol O, and :

the atomic number=8=number of electron

the atomic mass=16

The electron configuration based on the number of electrons(for Oxygen=8), so the configuration :

\tt _8^{16}O:1s^22s^22p^4 or we can write with noble gas [He] 2s²2p⁴

3 0
3 years ago
Air at 7S°F and14.6 though a cfm(cubic ft per minute) and the The flow rate is 48000 psia flows though a rectangular duct of Ix2
IgorLugansk [536]

Explanation:

The given data is as follows.

Air is at 75^{o}F and 14.6 psia.

\varepsilon = 0.00015 ft,     Flow rate, (Q) = 48000 ft^{3}/m

(a)  Formula to calculate hydraulic radius (r_{H}) is as follows.

              r_{H} = \frac{\text{free flow area}}{\text{wet perimeter}}

                          = \frac{2 \times 1}{2(1) + 2(2)}

                          = \frac{1}{3} ft

Formula for equivalent diameter is as follows.

                     D_{eq} = 4 \times r_{H}

                                    = 4 \times \frac{1}{3} ft  

                                    = \frac{4}{3} ft

(b)    Formula for velocity floe is as follows.

                         Q = VA

                     V = \frac{Q}{A}

                        = \frac{48000}{2 \times 1} ft/min

                        = 24000 ft/min

(c)   Formula to calculate Reynold's number is as follows.

         R_{e} = \frac{D \times V \times \rho}{\mu}

                   = \frac{\frac{4}{3} \times 24000 \times 0.0744}{0.0443}  (as \rho = 0.0744 lb/ft^{3} and \mu = 0.0443 lb/ft. hr)

                   = 53742.66 hr/min  

As 1 hr = 10 min. So, 53742.66 hr/min \times \frac{60 min}{1 hr}

                            = 3224559.6

(d)   Formula to calculate pressure drop (\Delta P) is as follows.

              \frac{\Delta P}{L} = \frac{4f \rho V^{2}}{2Dg_{c}}

Putting the given values into the above formula as follows.

               \frac{\Delta P}{L} = \frac{4f \rho V^{2}}{2Dg_{c}}

                      = \frac{4 \times 0.00015 \times 100 \times 0.0744 \times (24000)^{2}}{2 \times \frac{4}{3} \times {4}{3}}

                      = 6.238 lb/ft^{2}

5 0
3 years ago
Metals experience plastic deformation when _____.
xxTIMURxx [149]

Metals experience plastic deformation when a specific amount of pressure and temperature is applied to them. Most metals have low specific heat. Because of their low specific heat, they easily get hot when heat is applied to them.

3 0
3 years ago
What is the percent of O in CO2
zmey [24]

72.71 . simple google search, you shouldnt waste points

5 0
3 years ago
Read 2 more answers
A Rolaids tablet contains calcium for neutralizing stomach acid. if a Rolaids tablet neutralizes 24.65ml of 0.547m hydrochloric
Lelu [443]

There are 674 mg of calcium carbonate in a Rolaids tablet

<h3>Further explanation</h3>

Reaction

CaCO₃ + 2HCl ⇒ CaCl₂ + CO₂ +H₂O

V HCl = 24.65 ml

M HCl = 0.547

mol HCl :

\tt 24.65\times 0.547=13.48~mlmol

ratio mol CaCO₃ : HCl = 1 : 2, so mol CaCO₃ :

\tt \dfrac{1}{2}\times 13.48=6.74~mlmol=6.74\times 10^{-3}~mol

mass of CaCO₃ (MW=100~g/mol) :

\tt 6.74\times 10^{-3}\times 100=0.674~g=674~mg

4 0
3 years ago
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