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nordsb [41]
4 years ago
13

HELP! Question 11.

Chemistry
1 answer:
xxMikexx [17]4 years ago
6 0

Answer:

Warm front Forms when a moist, warm air mass slides up and over a cold air mass. As the warm air mass rises, it condenses into a broad area of clouds. A warm front brings gentle rain or light snow, followed by warmer, milder weather.

Your answer is B.

Enjoy.

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When carbon is burned in air, it reacts with oxygen to form carbon dioxide. When 22.8g of carbon were burned in the presence of
rosijanka [135]

Answer:

83.6 g  

Explanation:

The limiting reactant is carbon and oxygen is in excess.

C + O₂ ⟶ CO₂

Data:

                  Mass of C = 22.8 g

                 Mass of O₂ = 78.0 g

Mass of unreacted O₂ =  17.2 g

Calculations:

          Mass of O₂ reacted = 78.0 g  -  17.2 g = 60.8 g

Mass of reactants (C + O₂) = 22.8 g + 60.8 g = 83.6 g

According to the Law of Conservation of Mass, the mass of the product (CO₂) equals the sum of the masses of the reactants.

The mass of CO₂ is 83.6 g.

3 0
3 years ago
What mass of N2O5 will result from the reaction of 6.0 mol of NO2 if there is a 61.1% yield in the reaction
Nata [24]

Answer:

2.0 × 10² g

Explanation:

Step 1: Write the balanced equation

2 NO₂ + 0.5 O₂ ⇒ N₂O₅

Step 2: Calculate the theoretical yield, in moles, of N₂O₅

The molar ratio of NO₂ to N₂O₅ is 2:1.

6.0 mol NO₂ × 1 mol N₂O₅/2 mol NO₂ = 3.0 mol N₂O₅

Step 3: Calculate the theoretical yield, in grams, of N₂O₅

The molar mass of N₂O₅ is 108.01 g/mol.

3.0 mol × 108.01 g/mol = 3.2 × 10² g

Step 4: Calculate the real yield, in grams, of N₂O₅

real yield = theoretical yield × percent yield

real yield = 3.2 × 10² g × 61.1% = 2.0 × 10² g

6 0
3 years ago
Repulsion is a force or interaction among the atoms in a molecule in which the atoms attract one another.
Anni [7]
Repulsion is a force or interaction among the atoms in a molecule in which the atoms REPEL one another. By the word itself repulsion, meaning to repel, it automatically bans the idea of ATTRACTION. Therefore, the statement above is FALSE. The answer to this question is "B. False". 
3 0
3 years ago
A spirit burner used 1.00 g methanol to raise the temperature of 100.0 g water in a metal can from 28.00C to 58.0C. Calculate th
Andreas93 [3]

Complete question:

A spirit burner used 1.00 g methanol to raise the temperature of 100.0 g water in a metal can from 28.00C to 58.0C. Calculate the heat of combustion of methanol in kJ/mol.

Answer:

the heat of combustion of the methanol is 402.31 kJ/mol

Explanation:

Given;

mass of water, m_w = 100 g

initial temperature of water, t₁ = 28 ⁰C

final temperature of water, t₂ = 58 ⁰C

specific heat capacity of water = 4.184 J/g⁰C

reacting mass of the methanol, m = 1.00 g

molecular mass of methanol = 32.04 g/mol

number of moles = 1 / 32.04

                             = 0.0312 mol

Apply the principle of conservation of energy;

n\Delta H_{methanol} = Q_{water}\\\\n\Delta H_{methanol} =  mc\Delta t\\\\n\Delta H_{methanol} =  100 \times 4.184\times (58-28)\\\\n\Delta H_{methanol} =  12,552 \ J\\\\n\Delta H_{methanol} =  12.552 \ kJ\\\\\Delta H_{methanol} = \frac{12.552}{n} \\\\H_{methanol} = \frac{12.552 \ kJ}{0.0312 \ mol} \\\\\Delta H_{methanol} = 402.31 \ kJ/mol

Therefore, the heat of combustion of the methanol is 402.31 kJ/mol

                       

5 0
3 years ago
Choose the word that best completes this sentence. Welding in confined spaces or on stainless steel generates _____________ a ve
Drupady [299]
<span>Welding in confined spaces or on stainless steel generates (B) Hexavalent Chromium a very toxic chemical. Hexavalent chromium are chemical compounds that has a chromium with an oxidation state of +6. It is commonly used in textile dyes and wood preservation to avoid corrosion and conversion coatings.</span>
5 0
3 years ago
Read 2 more answers
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