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defon
2 years ago
15

What is the molar mass of NaCl? If you need to add 0.2 moles of NaCl to 500 mL of water, how many grams of NaCl do you need to a

dd?
Chemistry
1 answer:
stealth61 [152]2 years ago
6 0

Answer:

321 g

Explanation

All you need to know here is that the molarity of a solution tells you the number of moles of solute present in exactly

1 L

of the solution.

In your case, a

2.20-M

sodium chloride solution will contain

2.20

moles of sodium chloride, the solute, for every

1 L

of the solution.

So if every

1 L

of this solution must contain

2.20

moles of sodium chloride in order for the solution to have a molarity of

2.20 M

, it means that

2.50 L

of this solution must contain

2.50

L solution

⋅

2.20 moles NaCl

1

L solution

=

5.50 moles NaCl

To convert the number of moles of sodium chloride to grams, use the molar mass of the compound.

5.50

moles NaCl

⋅

58.4 g

1

mole NaCl

=

321 g

−−−−−

The answer is rounded to three sig figs.

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The standard on which the atomic mass unit is based is the mass of a
pashok25 [27]

Answer;

D. carbon-12 atom

Explanation;

-One atomic mass unit is the mass that is exactly equal to one-twelfth the mass of one carbon-12 atom. Therefore, the mass of carbon-12 is 12 amu and this provides the standard that is used in measuring the atomic mass of all other elements.

-The atomic mass of carbon is 12.01 and not 12.00 in the periodic table.

-Due to the fact that there are more than one element for most naturally occurring elements, the average mass of the naturally occurring mixture of isotopes is taken while determining the atomic mass of an element.

3 0
2 years ago
Which choice(s) correctly rank(s) the bonds in terms of increasing polarity?
Marina CMI [18]

Answer:

(II) only correctly rank the bonds in terms of increasing polarity.

Explanation:

Bond polarity is proportional to difference in electronegativity between bonded atoms.

Atoms    Electronegativity          Bond        Electronegativity difference

Cl                          3.0                       Cl-F                      1.0

Br                          2.8                       Br-Cl                     0.2

F                            4.0                       Cl-Cl                      0

H                            2.1                       H-C                       0.4

C                            2.5                       H-N                       0.9

N                             3.0                      H-O                       1.4

O                             3.5                      Br-F                       1.2

I                               2.7                      I-F                         1.3

Si                             1.9                      Cl-F                       1.0  

P                              2.2                      Si-Cl                      1.1

                                                          Si-P                        0.3

                                                          Si-C                        0.6

                                                           Si-F                        2.1

So, clearly, order of increasing polarity : O-H > N-H > C-H

So, (II) only correctly rank the bonds in terms of increasing polarity

4 0
3 years ago
How many kilojoules are released when 8.2 g of water condenses at 100 °c and cools to 15 °c?
MrRa [10]

Answer:- 2.92 kJ of heat is released.

Solution:- We have water at 100 degree C and it's going to be cool to 15 degree C.

So, change in temperature, \Delta T = 15 - 100 = -85 degree C

mass of water, m = 8.2 g

specific heat of water, c = 4.184\frac{J}{^0C.g}

The equation used for solving this type of problems is:

q=mc\Delta T

Let's plug in the values in the equation and solve it for q which is the heat energy:

q = (8.2)(4.184)(-85)

q = -2916.248 J

They want answer in kJ. So, let's convert J to kJ and for this we divide by 1000.

q=-2916.248J(\frac{1kJ}{1000J})

q = -2.92 kJ

Negative sign indicates the heat is released. So, in the above process of coiling of water, 2.92 kJ of heat is released.

3 0
3 years ago
Why is only one diastereomer formed in this reaction? Relate your answer to the mechanism you drew. b) If you used cis-stilbene
crimeas [40]

Answer:

1. Diastereomers have different physical properties (unlike most aspects of enantiomers) and often different chemical reactivity. ... Many conformational isomers are diastereomers as well. Diastereoselectivity is the preference for the formation of one or more than one diastereomer over the other in an organic reaction.

2. The result is a trans dibromide, as shown in the equation below

Explanation:

Diastereomers (sometimes called diastereoisomers) are a type of a stereoisomer.[1] Diasteoreomers are defined as non-mirror image non-identical stereoisomers. Hence, they occur when two or more stereoisomers of a compound have different configurations at one or more (but not all) of the equivalent (related) stereocenters and are not mirror images of each other.[2] When two diastereoisomers differ from each other at only one stereocenter they are epimers. Each stereocenter gives rise to two different configurations and thus typically increases the number of stereoisomers by a factor of two.

2. the addition of bromine to the trans and

cis isomers of 1,2-diphenylethene, more commonly known as trans- and cis-stilbene.

H

H

H H

trans-stilbene cis-stilbene

m.p. 122-124°C b.p. 82-84°C

density 0.970 g/mL density 1.011 g/mL

M.W. 180.25 g/mol M.W. 180.25 g/mol

In both cases, the nucleophilic double bond undergoes an electrophilic addition reaction

by the bromine reagent which proceeds via a cyclic bromonium ion. The addition of

bromine begins at one side of the double bond (either side is equally likely, but only one

option is drawn) and is followed by attack of bromide ion on the bromonium ion (again,

attack could occur at either carbon since the ion is symmetric, but only one option is

drawn). The result is a trans dibromide, as shown in the equation below:

Since the cis and trans isomers of stilbene have different geometries, it follows

that upon reaction with bromine they give rise to stereoisomeric bromonium ions and,

eventually, products that differ only by their stereochemistry.

4 0
3 years ago
if you are told to get 100 mL of stock solution to use to prepare smaller size sample for an experiment, which piece of glasswar
fgiga [73]

Answer:

A beaker  

Step-by-step explanation:

Specifically, I would use a 250 mL graduated beaker.

A beaker is appropriate to measure 100 mL of stock solution, because it's easy to pour into itscwide mouth from a large stock bottle.

You don't need precisely 100 mL solution.

If the beaker is graduated, you can easily measure 100 mL of the stock solution.

Even if it isn't graduated, 100 mL is just under half the volume of the beaker, and that should be good enough for your purposes (you will be using more precise measuring tools during the experiment).

6 0
2 years ago
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