Answer:
Mass of seawater = 512.5 gram
Explanation:
Given:
Volume of seawater = 500 ml
Density of seawater = 1.025 g/ml
Find:
Mass of seawater
Computation:
Mass of seawater = Volume of seawater × Density of seawater
Mass of seawater = 500 × 1.025
Mass of seawater = 512.5 gram
Answer:
c
Explanation:
hope it helps ...........
In any redox reaction, the substance that undergoes reduction will 3) <span> gain electrons and have a decrease in oxidation number.</span>
Answer:
20 ounces of 14% solution and 8 ounces of 7% solution.
Explanation:
Let the amount of 14% solution required be A and the amount of 7% solution required be B.
Mixture of A and B must give 28 ounces:
A + B = 28 ................. Eqn 1
Also, mixture of 14% A and 7% B must give 12%, 28 ounces solution:
0.14A + 0.07B = 0.12(28) = 3.36...................Eqn 2
From eqn 1, B = 28 - A, eqn 2 becomes:
0.14A + 0.07(28 - A) = 3.36
0.07A = 3.36 - 1.96
A = 20 ounces
Substitute the value of A into eqn 1 to get B:
20 + B = 28
B = 8 ounces.
Hence, 20 ounces of 14% hydrochloric acid and 8 ounces of 7% hydrochoric acid should be mixed together in order to get 28 ounces of 12% solution.
Answer:
Explanation:
Group Most Likely Ionic Charge Number of Valence Electrons
I +1 1
II +2 2
III +3 3
IV +4 or -4 4
V -3 5
VI -2 6
VII -1 7
VIII 0 8
For elements in group IV and above, their ionic charge is (8-number of their valence electrons.)
