Answer:
SO₂ + 0.5 O₂ + H₂O → H₂SO₄
3.83 g
Explanation:
In the formation of acid rain, sulfur dioxide reacts with oxygen and water in the air to form sulfuric acid. The balanced chemical equation is:
SO₂ + 0.5 O₂ + H₂O → H₂SO₄
The molar mass of SO₂ is 64.07 g/mol. The moles of SO₂ corresponding to 2.50 g are:
2.50 g × (1 mol/64.07 g) = 0.0390 mol
The molar ratio of SO₂ to H₂SO₄ is 1:1. The moles of H₂SO₄ formed are 0.0390 moles.
The molar mass of H₂SO₄ is 98.08 g/mol. The mass of H₂SO₄ is:
0.0390 mol × 98.08 g/mol = 3.83 g
When the temperature increases, the kinetic energy of the particles increase this inturn makes them vibrate
NaOH reacts with CH3COOH in 1:1 molar ratio to produce CH3COONa
NaOH + CH3COOH → CH3COONa + H2O
Mol CH3COOH in 52.0mL of 0.35M solution = 52.0/1000*0.35 = 0.0182 mol CH3COOH
Mol NaOH in 19.0mL of 0.40M solution = 19.0/1000*0.40 = 0.0076 mol NaOH
These will react to produce 0.0076 mol CH3COONa and there will be 0.0182 - 0.0076 = 0.0106 mol CH3COOH remaining in solution unreacted . Total volume of solution = 52.0+19.0 = 71mL or 0.071L
Molarity of CH3COOH = 0.0106/0.071 = 0.1493M
CH3COONa = 0.0076 / 0.071 = 0.1070M
pKa acetic acid = - log Ka = -log 1.8*10^-5 = 4.74.
pH using Henderson - Hasselbalch equation:
pH = pKa + log ([salt]/[acid])
pH = 4.74 + log ( 0.1070/0.1493)
pH = 4.74 + log 0.717
pH = 4.74 + (-0.14)
pH = 4.60.
Answer:
Mg would blow off. AI would be affective to copper but not to MG
Explanation:
True. Mitosis is a part of the call cycle when replicated chromosomes are separated into new nuclei. It is a for if eukaryotic cell division that produces two daughter cells with the same genetic components as the parent cells.
