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3 years ago

The standard on which the atomic mass unit is based is the mass of a

Chemistry

1 answer:

pashok25 [27]3 years ago

3 0

Answer;

D. carbon-12 atom

Explanation;

-One atomic mass unit is the mass that is exactly equal to one-twelfth the mass of one carbon-12 atom. Therefore, the mass of carbon-12 is 12 amu and this provides the standard that is used in measuring the atomic mass of all other elements.

-The atomic mass of carbon is 12.01 and not 12.00 in the periodic table.

-Due to the fact that there are more than one element for most naturally occurring elements, the average mass of the naturally occurring mixture of isotopes is taken while determining the atomic mass of an element.

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Give the IUPAC name for the following structure: 3-chloro-6-methylcyclohexanol 2-methyl-5-chlorocyclohexanol 1-chloro-4-methylcy

Shtirlitz [24]

Answer:

5-chloro-2-methylcyclohexanol

Explanation:

There is no structure for the compound, but we can analyze the proposed options using the IUPAC rules to name organic compounds.

IUPAC rules state that to name an organic compound, first we have to identify the priorities for the functional groups present in the compound. In this case, the priority functional group is the alcohol group, so we will start the counting of the carbons in this group. Then, the counting of carbon atoms is followed by the next substituents so they have the lowest possible numbers, in this case, we can assign the number 2 to the methyl group and 5 to the chloride group, and name the compound in alphabetical order, using commas to separate the words from the numbers and with no space between the words.

Since the other options involve: high countings for the susbtituents groups (3-chloro-6-methylcyclohexanol), wrong assignation of priority functional group (1-chloro-4-methylcyclohexanol), wrong sequence of counting in the compound (2-methyl-3-chlorocyclohexanol) and no alphabetical order to name the compound (2-methyl-5-chlorocyclohexanol), the correct option is:

5-chloro-2-methylcyclohexanol

Have a nice day!

4 0

4 years ago

Nacl is an ionic solid. the na+ and cl− ions in nacl are bonded through an electrostatic force of attraction commonly known as t

Murrr4er [49]

NaCl is poster-compound for ionic bonding. The bonds in NaCl have about 70% ionic character, making the bond highly polar. its overstatement to state that there is actual ion in NaCl with +1 and -1 charge but actual charge of Na and Cl is +1 and -1 ion, since Nacl exist as a network of highly charged particle and not discrete molecule, NaCl particle does not exhibit intermolecular forces. Water molecule on other hand exhibit London dispersion force, keesom force, and hydrogen bonding. The polar water molecule are attracted to the polarized Na and Cl atoms. This is what allow NaCl(s) to dissolve and ionize in water. Therefore type of attraction in NaCl is ion-dipole attraction.

7 0

3 years ago

1. How does the field of science gain knowledge and understanding?(1 point)

goblinko [34]

Answer: good luck with that F

Explanation:

8 0

3 years ago

How do mutations affect a species ability to survive and reproduce? Justify your response in two or more complete sentences.

olga nikolaevna [1]

Mutation affect a species ability to survive and reproduce. Mutations can expand the life span of a species by keeping them hidden from predators which would also increase reproduction. If exposed to other wildlife, those numbers could decrease.

3 0

3 years ago

Read 2 more answers

A una mezcla de 300g, formada con 60% P/P de Hierro y 40% P/P de Arena, se le adicionan 135g de Cobre y 2,77g de Aluminio. ¿Cuál

Svetllana [295]

Answer:

$\%P/P_{hierro}=41.1\%\\\\\%P/P_{arena}=24.4\%\\\\\%P/P_{cobre}=30.8\%\\\\\%P/P_{aluminio}=0.6\%$

Explanation:

¡Hola!

En este caso, dado que estamos tratando con problem sobre porcentaje peso/peso de hierro, arena, cobre y aluminio, primero debemos calcular la masa inicial de estos dos primeros en la mezcla original de acuerdo con:

$m_{hierro}=300g*0.60=180g\\\\m_{arena}=300*0.40=120g$

Ahora si podemos calcular la masa de la mezcla final como la suma de las masas de todos los constituyentes de la mezcla:

$m_T=180g+120g+135g+2.77g=437.77g$

Finalmente, podemos calcular los porcentajes P/P como se muestra a continuación:

$\%P/P_{hierro}=\frac{180g}{437.77g} *100\%=41.1\%\\\\\%P/P_{arena}=\frac{120g}{437.77g} *100\%=24.4\%\\\\\%P/P_{cobre}=\frac{135g}{437.77g} *100\%=30.8\%\\\\\%P/P_{aluminio}=\frac{g}{437.77g} *100\%=0.6\%$

¡Saludos!

5 0

3 years ago