How many kilojoules are released when 8.2 g of water condenses at 100 °c and cools to 15 °c?
1 answer:
Answer:- 2.92 kJ of heat is released.
Solution:- We have water at 100 degree C and it's going to be cool to 15 degree C.
So, change in temperature, = 15 - 100 = -85 degree C
mass of water, m = 8.2 g
specific heat of water, c =
The equation used for solving this type of problems is:
Let's plug in the values in the equation and solve it for q which is the heat energy:
q = (8.2)(4.184)(-85)
q = -2916.248 J
They want answer in kJ. So, let's convert J to kJ and for this we divide by 1000.
q = -2.92 kJ
Negative sign indicates the heat is released. So, in the above process of coiling of water, 2.92 kJ of heat is released.
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Explanation:
Chemical reaction equation for the give decomposition of is as follows:.
And, initially only is present.
The given data is as follows.
= 2.3 atm at equilibrium
= 0.69 atm
Therefore,
= 0.23 aatm
So, = 2.3 - 2(0.23)
= 1.84 atm
Now, expression for will be as follows.
=
= 0.0224
or,
Thus, we can conclude that the pressure equilibrium constant for the decomposition of ammonia at the final temperature of the mixture is .
Answer:
The percent yield is 42.52%.
Explanation:
Theoretical yield of beryllium chloride = 12.7 g
Actual yield of the beryllium chloride = 5.4 g
The formula used for the percent yield will be :
Now put all the given values in this formula, we get:
The percent yield is 42.52%.