1 year ago

As the wavelength of electromagnetic radiation increase

Physics

1 answer:

Dominik [7]1 year ago

7 0

Answer:

the frequency and the radiation of radiation decreases.

Explanation:

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The gravitational force of a star on an orbiting planet 1 is f1. planet 2, which is three times as massive as planet 1 and orbit

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Let us consider two bodies having masses m and m' respectively.

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From the above we see that F ∝ mm' and $F\alpha \frac{1}{r^{2} }$

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Let the mass of central star is m .

Hence the gravitational force for planet A is $f_{1} =G \frac{m_{1}*m }{r^{2} }$

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Hence the gravitational force $f_{2} =G\frac{m m_{2} }{r^{2} }$

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$= \frac{3}{4} G\frac{mm_{1} }{r_{1} ^{2} }$

Hence the ratio is $\frac{f_{2} }{f_{1} } = \frac{\frac{3}{4}G mm_{1/r_{1} ^2} }{Gmm_{1}/r_{1} ^2 }$

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