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Setler [38]
3 years ago
9

What did the asymptote say to the removable discontinuity worksheet answers?

Physics
1 answer:
ra1l [238]3 years ago
6 0

“Don't hand that holier than thou line to me” is what the asymptote said to the removable discontinuity.

 

 

The distance between the curve and the line where it approaches zero as they tend to infinity is the line in the asymptote of a curve. This is unusual for modern authors but in some sources the requirement that the curve may not cross the line infinitely often is included.

 

The point that does not fit the rest of the graph or is undefined is called a removable discontinuity. By filling in a single point, the removable discontinuity can be made connected.

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Answer:

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3 years ago
How could you have collected your data in different ways that may have more accurately identified the Seymouria?
Pepsi [2]

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8 0
3 years ago
A tension force of 175 N inclined at 20.0° above the horizontal is used to pull a 40.0 - kg packing crate a distance of 6.00 m o
Murljashka [212]

Answer:

(a) Work done by the tension force is 987 J

(b) Coefficient of kinetic friction between the crate and surface is 0.495

Explanation:

(a)

Work done by any force F in moving an object by a distance d making an angle \Theta with the direction of force  is given by

W=Fd\cos (\Theta )

W=175 \times 6 \times  \cos (20 )J=987J

Thus work done by the tension force is 987 J

(b)

Normal force on the crate is given by

N= mg-F\sin \Theta  =(40\times 9.8-175\times \sin 20)Newton

=>N=332 Newtons

Since crate is moving with constant speed . Therefore using Newtons second law .

Fcos(\Theta ) -\mu_k N=0

Where \mu_k=coefficient of kinetic friction

\therefore \mu_k=\frac{F\cos (\Theta )}{N}

=>\mu_k=\frac{175\times \cos 20}{332}

=>\mu _k= 0.495

Thus coefficient of kinetic friction between the crate and surface is 0.495

4 0
3 years ago
In the two-slit experiment, monochromatic light of frequency 5.00 × 1014 Hz passes through a pair of slits separated by 2.20 × 1
Lyrx [107]

Answer:

\theta=4.64^{\circ}

Explanation:

It is given that,

The frequency of monochromatic light, f=5\times 10^{14}\ Hz

Slit separation, d=2.2\times 10^{-5}\ m

Let \theta is the angle away from the central bright spot the third bright fringe past the central bright spot occur. The condition for bright fringe is :

d\ sin\theta=n\lambda

n = 3

\lambda=\dfrac{c}{f}

d\ sin\theta=\dfrac{nc}{f}        

sin\theta=\dfrac{nc}{fd}        

sin\theta=\dfrac{3\times 3\times 10^8}{5\times 10^{14}\times 2.2\times 10^{-5}}  

\theta=4.64^{\circ}

So, at 4.64 degrees the third bright fringe past the central bright spot occur. Hence, this is the required solution.

3 0
3 years ago
1. The hydrogen balloons which are used to collect weather information from the atmosphere is made of plastic and never complete
Naily [24]

Answer:

Answer:- Volume of the balloon is 5.78 L.

Solution:- There are 0.24 moles of hydrogen gas in a balloon at 35 degree C and 1.05 atm pressure. It asks to calculate the volume of the balloon.

This problem is based on ideal gas law equation:

P = 1.05 atm, n = 0.24 mole, T = 35 + 273 = 308 K

R =

V = ?

The equation could be rearranged for the volume as:

Let's plug in the values and do the calculations to get the volume of the balloon:

V = 5.78 L

So, the volume of the gas balloon is 5.78 L.

5 0
2 years ago
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