All categories

4 years ago

When was the first electric typewriter produced and by what company

1 answer:

6 0

In 1920, after returning from Army service, he produced a successful model and in 1923 turned it over to the Northeast Electric Company of Rochester for development.

You might be interested in

....................................................

iragen [17]

....................................

8 0

3 years ago

Read 2 more answers

Position coordinate of a particle confined to

Gelneren [198K]

Answer:

a) 4 s

b) 36 m/s²

c) 54 m

Explanation:

s = 2t³ – 24t + 6

a) Find t when v = 72 m/s.

v = ds/dt

v = 6t² – 24

72 = 6t² – 24

6t² = 96

t = 4

b) Find a when v = 30 m/s.

a = dv/dt

a = 12t

When v = 30:

30 = 6t² – 24

6t² = 54

t = 3

a = 36

c) Find Δs between t = 1 and t = 4

Δs = (2(4)³ – 24(4) + 6) – (2(1)³ – 24(1) + 6)

Δs = 38 – (-16)

Δs = 54

8 0

4 years ago

You are standing next to your friend, ready to race across a 100 meter field. When the go signal is given, you take 5 seconds to

zhuklara [117]

1) 1.08 m/s^2

Explanation:

Acceleration is equal to the change in velocity divided by the time taken:

$a=\frac{v-u}{\Delta t}$

where

v is the final velocity

u is the initial velocity

$\Delta t$ is the time taken

In this problem, we have:

- initial velocity: u = 0 (you start from rest)

- final velocity: v = 5.4 m/s

- time taken: $\Delta t = 5 s$

Therefore, the acceleration is

$a=\frac{v-u}{\Delta t}=\frac{5.4 m/s-0}{5 s}=1.08 m/s^2$

2) -0.54 m/s^2

We can calculate the acceleration to slow down using the same formula as before, but this time the data are as follows:

- initial velocity : u = 5.4 m/s

- final velocity : v = 0 (you come to a stop)

- time taken : $\Delta t = 10 s$

using the same formula, we find

$a=\frac{v-u}{\Delta t}=\frac{0-5.4 m/s}{10 s}=-0.54 m/s^2$

And the negative sign means it is a deceleration.

5 0

3 years ago

A car is traveling due north at 23.6 m>s.

alexira [117]

A car is traveling due north at 23.6 m>s.

Find the velocity of the car after 7.10 s if its

acceleration is

The acceleration is known to be: a(t) = 1.7 m/s2.

We must integrate over time to obtain the velocity function, and the results are:

v(t) = (1.7m/s^2)

*t + v0

If we suppose that we begin at 23.6 m/s, then the initial velocity is: v0 = 23.6 m/s, where v0 is the beginning velocity.

The velocity formula is then: v(t) = (1.7m/s2).

*t + 23.6 m/s

We now seek to determine the value of t such that v(t) = 27.8 m/s.

Consequently, v(t) = 27.8 m/s = (1.7 m/s2)

*t + 23.6 m/s = (1.7 m/s2) 27.8 m/s - 23.6 m/s

t = 2.5 seconds when *t 4.2 m/s = (1.7 m/s/2)

At such acceleration, 2.5 seconds are required.

To learn more about acceleration Visit :

brainly.com/question/19599982

#SPJ9

4 0

2 years ago

A large aquarium of height 6 m is filled with fresh water to a depth of D = 1.50 m. One wall of the aquarium consists of thick p

Vesnalui [34]

Answer

given,

height of aquarium = 6 m

Depth of fresh water = D = 1.50 m

horizontal length of the aquarium(w) = 8.40 m

total force increased when liquid is filled to depth = 4.30 m

g = 9.81 m/s²

ρ = 998 Kg/m³

force in the aquarium.

dF = PdA

$F = \int PdA$

$F = \int \rho\ g\ y\ (wdy)$

$F = \rho\ g\ w \int ydy$

$F = \rho\ g\ w\dfrac{y^2}{2}$

$F = \dfrac{\rho\ g\ w\ y^2}{2}$

At D = 1.5 m

$F = \dfrac{980\times 9.8\times 8.4\times 1.5^2}{2}$

F = 9.08 x 10⁴ N

At D = 4.30 m

$F = \dfrac{980\times 9.8\times 8.4\times 4.3^2}{2}$

F = 7.46 x 10⁵ N

Total force on the wall increased by

ΔF = 74.6 x 10⁴ - 9.08 x 10⁴

ΔF = 65.52 x 10⁴ N

5 0

3 years ago