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ryzh [129]
3 years ago
5

Suppose you find yourself in a spaceship in a uniform circular orbit around a star. Suppose also that that star is going to lose

half of its mass over some period of time (which would, of course, change the magnitude of the force of gravity keeping you in orbit). If you wanted to keep the same orbital speed in a uniform circular orbit after the star has only half of its current mass, how should you relocate your spaceship
Physics
1 answer:
neonofarm [45]3 years ago
3 0

Answer:

i actually have no idea...

Explanation:

i have no brain

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The plane of a5cm*8cm rectangular loop of wire is parallel to a 0.19T magnetic field the loop carries a current of 6.2 A. What t
Sedaia [141]

Answer:

Torque; τ = 4.712 × 10^(-3) J

Magnetic moment; M = 0.0248 J/T

Explanation:

Torque is gotten from the formula;

τ = BIA

Where;

B is magnetic field

I is current

A is area

We are given;

B = 0.19T

I = 6.2A

Rectangle dimensions = 5cm by 8cm = 0.05m by 0.08m

Thus;

Area; A = 0.05m × 0.08m = 0.004 m²

Thus;

τ = 0.19 × 6.2 × 0.004

τ = 4.712 × 10^(-3) J

Formula for the magnetic moment is given by;

M = IA

M = 6.2 × 0.004

M = 0.0248 J/T

5 0
3 years ago
Who was the first scientist to propose that an object could emit only certain amounts of energy?
Rzqust [24]
It was Niels Bohr who proposed it
3 0
3 years ago
For which pair of launch angles will two identical projectiles have equal ranges?. A. 19.24°, 80.54°B. 16.42°, 74.58°C. 60.23°,
AlladinOne [14]
The kinematic equations of motion that apply here are<span>y(t)=votsin(θ)−12gt2</span>and<span>x(t)=votcos(θ)</span>Setting y(t)=0 yields <span>0=votsin(θ)−12gt2</span>. If we solve for t, we obtain, by factoring,<span>t=<span>2vsin(θ)g</span></span>Substitute this into our equation for x(t). This yields<span>x(t)=<span><span>2v2cos(θ)sin(θ)</span>g</span></span><span>This is equal to x=<span><span>v^2sin(2θ)</span>g</span></span>Hence the angles that have identical projectiles are have the same range via substitution in the last equation is C. <span> 60.23°, 29.77° </span>
4 0
3 years ago
Read 2 more answers
Need help on this please
marin [14]
The answer is D, the amount of energy stays the same.
3 0
3 years ago
Using the graph predict how many paper clipsa 7.5 v battery would pick up for both the 25 coil electromagnet and the 50 coil ele
enyata [817]

The graph between the strength of the magnet(number of paper clips picked) and battery is approximately a straight line.

For 25 coil, with increase of 1.5 V battery voltage, the electromagnet picks about 5 more clips. So, for a 7.5 V battery, it would pick about 30 paper clips.

For 50 coil, with increase of 1.5 V battery voltage, the electromagnet picks about 15 more clips. So, for a 7.5 V battery, it would pick about 30 paper clips.

3 0
3 years ago
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