Suppose you find yourself in a spaceship in a uniform circular orbit around a star. Suppose also that that star is going to lose
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Answer:
The generator produces electrical energy at a rate of 1378125000 J per second.
Explanation:
volume of water falling each second is 1250
height through which it falls, h is 150 m
mass of 1 of water is 1000 kg
⇒mass of 1250 of water, m = 1250×1000 = 1250000 kg
acceleration due to gravity, g = 9.8
in falling through 150 m in each second, by Work-Energy Theorem:
Kinetic Energy(KE) gained by it = Potential Energy(PE) lost by it
⇒KE = mgh
= 1250000×9.8×150 J
= 1837500000 J
Electrical Energy = (KE)
= ×1837500000
= <u>1378125000 J per second</u>