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Mama L [17]
2 years ago
11

Create your own simple metaphor illustrating how demand and supply work together to create equilibrium. Label the following on y

our metaphor: quantity demanded, quantity supplied, equilibrium point
Physics
1 answer:
alina1380 [7]2 years ago
3 0

''When the quantity demanded intersect with quantity supplied, it leads o the formation of equilibrium point.''

<h3>How equilibrium occur?</h3>

The equilibrium price and equilibrium quantity occur where the supply and demand curves cross with each other. The equilibrium occurs when the quantity demanded is equal to the quantity supplied.

So we can conclude that  when the quantity demanded intersect with quantity supplied, it leads o the formation of equilibrium point.

Learn more about equilibrium here: brainly.com/question/517289

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Answer:

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Which one of the statements below is true about mechanical waves?
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What is the speed of light (in m/s) in air? (Enter your answer to at least four significant figures. Assume the speed of light i
jenyasd209 [6]

Answer:

The speed of light in air is 2.996x10⁸ m/s, and polystyrene is 1.873x10⁸ m/s.

Explanation:

To find the speed of light in air and in polystyrene we need to use the following equation:

c_{m} = \frac{c}{n}

Where:

c_{m}: is the speed of light in the medium

n: is the refractive index of the medium

In air:

c_{a} = \frac{c}{n_{a}} = \frac{2.997 \cdot 10^{8} m/s}{1.0003} = 2.996 \cdot 10^{8} m/s

In polystyrene:

c_{p} = \frac{c}{n_{p}} = \frac{2.997 \cdot 10^{8} m/s}{1.6} = 1.873 \cdot 10^{8} m/s  

Therefore, the speed of light in air is 2.996x10⁸ m/s, and polystyrene is 1.873x10⁸ m/s.

I hope it helps you!

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3 years ago
Calculate the amount of heat (in kj) required to convert 74.6 g of water to steam at 100°c
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You just need the energy of turning of water in to steam. Water is a little funny because once water gets to 100 degrees C, it stops changing in temperature whilst it all turns to steam. The amount of energy required to turn 1 gram of water into steam is 2257 Joules. We call this the latent heat of vaporisation. So to turn 74.6 grams of water to steam, you would need:

2257J/gram x 74.6g = 168,372.2 J = 168.4 kJ

(<span></span><em>latent heat of vaporisation: 2257 J/gram</em>)


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