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Rus_ich [418]
3 years ago
8

A hawk leaves its nest in Fort Worth and travels 3,000 meters east. After snacking on a tasty rodent the hawk flies another 1,50

0 meters east
Physics
1 answer:
Paha777 [63]3 years ago
6 0
I think the logical question here is to either find the distance or the displacement. They differ in such a way that distance is a scalar quantity that does not focus on the direction. Displacement is a vector quantity that covers the distance from the starting point to end point. Because it travels only in one direction (to the east), in this condition, distance is equal to displacement.

Distance =  Displacement = 3,000 m + 1,500 m = 4,500 m
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Jobisdone [24]
Trick question? In order to have kinetic energy, an object must be moving. Therefore, in this case, kinetic energy would be 0. If it were asking about potential energy, it would be a different story. 
8 0
3 years ago
Read 2 more answers
1)what is the momentum of a 40,000,000kg tanker traveling at 5 m/s?
Fittoniya [83]

Answer:

1)4*10^7 * 5= 2*10^8

2)50/10=5

5 0
3 years ago
An automobile engine can produce 153 N · m of torque. Calculate the angular acceleration (in rad/s^2) produced if 85.2% of this
galina1969 [7]

Answer:

46.2 rad/s2

Explanation:

Angular acceleration works very similar to linear acceleration, it follows this equation:

\gamma = \frac{Mt}{J}

Where:

γ: angular acceleration

Mt: torque

J: moment of inertia of the load from its turning axis

Since we have the torque we just need the moment of inertia. We have to add together the moments of the drive shaft, tires, wheel walls and wheels.

The wheels act like disks. For disks the moment of inertia is:

J = \frac{1}{2} * m * r^2

Jwheel = \frac{1}{2} = 15 * 0.18^2 = 0.243 kg*m^2

The wheel walls act like annular rings, for these the moment of inertia is:

J = \frac{1}{2} * m * (re^2 - ri^2)

Jwall = \frac{1}{2} * 2 * (0.32^2 - 0.18^2) = 0.07 kg * m^2

The tread acts like a hoop, as in mass concentrated into a circunference, for these:

J = m * r^2

Jtread = 10 * 0.33^2 = 1.09 kg*m^2

The axle acts like a rod, which is the same as the disk:

Jaxle = \frac{1}{2} * 14.1 * 0.02^2 = 0.0028 kg*m^2

The drive shaft acts like a rod too:

Jshaft = \frac{1}{2} * 31.7 * 0.032^2 = 0.016 kg*m^2

SO, the total moment of inertia is:

J = 2*Jwheel + 2*Jwall + 2*Jtread + Jaxle + Jshaft

J = 2*0.243 + 2*0.07 + 2*1.09 + 0.0028 + 0.016 = 2.82 kg*m2

Finally the angular acceleration is:

\gamma = \frac{0.852 * 153}{2.82} = 46.2 \frac{rad}{s^2}

4 0
3 years ago
The radius of Earth is . The average Earth-Sun distance is . How many Earths would fit between Earth and the Sun if they are sep
Verdich [7]

Answer:

The radius of the earth is 6,371 km.

The average Earth-Sun distance is 152.09 million km

How many Earths would fit between Earth and the Sun if they are separated by their average distance? Approximately 11,936 Earths.

I didn't really understand the last part, but if you don't get a better answer please mark me as brainliest.

6 0
3 years ago
An electron is confined to a one dimensional infinite potential well 150 pm. How much energy must it absorb if it is to jump to
igor_vitrenko [27]

Answer:

\Delta E=1.22\times 10^{-22}J

Explanation:

The energy of electron in any state is given by E=\frac{n^2h^2}{8mL^2} here h is planck's constant n is state of electron L is the infinte potential well m is the mass of electron

We know that h=6.67\times 10^{-34}

Potential well dimension = 150pm=150\times 10^{-12}m

Mass of electron =9.1\times 10^{-31}kg

So energy required to electron to jump from ground state to 3rd state

\Delta E=\frac{h^2}{8mL^2}\left ( 3^2-1^2 \right )

\Delta E=\frac{\left ( 6.67\times 10^{-34} \right )^2}{8\times 9.1\times 10^{-31}(150\times 10^{-12})^2}\left ( 9-1 \right )

\Delta E=1.22\times 10^{-22}J

7 0
3 years ago
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