Two children of mass 18 kg and 29 kg sit balanced on a seesaw with the pivot point located at the center of the seesaw. If the c
hildren are separated by a distance of 5 m, at what distance from the pivot point is the small child sitting in order to maintain the balance?
1 answer:
Answer:
3.085 [m].
Explanation:
1) The rule:
m₁*g*l₁=m₂*g*l₂, where m₁ and l₁ - the mass and distance for the small child, m₂ and l₂ - for the big child;
2) according to the condigion l₁+l₂=5, then
3) it is possible to make up the system:
4) finally, l₁=145/47≈3.085 [m].
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