The grains in igneous rocks are interlocking but the Metamorphic rocks are not.
Answer:
Explanation:
The system can be modelled appropriately by the use of the Principle of Momentum Conservation and Impact Theorem:
The average force exerted on her:
Answer: Hello mate!
lets define the north as the y-axis and east as the x-axis.
Using the notation (x,y) we can define the initial position of the car as (0,0)
then the car travells 13 mi east, so now the position is (13,0)
then the car travels Y miles to the north, so the position now is (13, Y)
and we know that the final position is 25° degrees north of east of the initial position. This angle says that the distance traveled to the north is less than 13 mi because this angle is closer to the x-axis (or east in this case).
This angle is measured from east to north, then the adjacent cathetus is on the x-axis, in this case, 13mi
And we want to find the distance Y, so we can use the tangent:
Tan(25°) = Y/13
tan(25°)*13 mi = Y = 6.06 mi.
Answer:
<em>The correct option is C) spreads out over a large area on the object. </em>
Explanation:
In physics, a ground can be described as a reservoir object in which charge can be stored. Grounding refers to the removal of charge in an object by using the ground object. When an object with excess if charge is placed on the ground object, the electrons are transferred from the charges object to the ground object. This charge begins to spread evenly in the ground object with the passage of time.
Answer:
Tiempo, t = 6.11 segundos.
Explanation:
Dados los siguientes datos;
Distancia = 140 m
Aceleración = 7,5 m/s²
Dado que el objeto partió del reposo, su velocidad inicial es igual a 0 m/s.
Para encontrar el tiempo, usaríamos la segunda ecuación de movimiento;
S = ut + ½at²
Dónde;
S representa el desplazamiento o la altura medida en metros.
u representa la velocidad inicial medida en metros por segundo.
t representa el tiempo medido en segundos.
a representa la aceleración medida en metros por segundo cuadrado.
Sustituyendo en la ecuación, tenemos;
140 = 0*t + ½*7.5*t²
140 = 0 + 3.75t²
140 = 3.75t²
Dividiendo ambos lados por 3,75, tenemos;
t² = 140/3.75
t = √37.33
Tiempo, t = 6.11 segundos
