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cricket20 [7]
3 years ago
13

Do you think it is possible to control the magnetic properties of a magnet? Can a magnet be turned on and off? Explain your answ

er.
Physics
1 answer:
Brrunno [24]3 years ago
8 0

Answer:

Yes it is possible to control to some extent

Explanation:

Yes it is possible to control to some extent. Explanation: In general there are two types of magnets : permanent and temporary (electromagnets). ... On the other hand permanent magnet cannot be switched on and off but the magnetic properties can be altered event to an extent when it loses all its magnetic properties.

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A conductor carrying a current I = 13.8 A is directed along the positive x axis and perpendicular to a uniform magnetic field. A
Scorpion4ik [409]

Answer:

a) B=0.008 T

b) +z direction

Explanation:

<u>solution:</u>

a) The magnetic force:

        F=i*l*B

Solve for B:  

      B=0.008 T

b) According to the left hand rule, the magnetic field is in the +z direction

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What is carbon dating
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the determination of the age or date of organic matter from the relative proportions of the carbon isotopes carbon-12 and carbon-14 that it contains. The ratio between them changes as radioactive carbon-14 decays and is not replaced by exchange with the atmosphere.

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1.Un conductor este străbătut de un curent electric cu I = 1.
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3 years ago
THE WINNER WILL BE AWARDED THE BRAINLIEST PLEASE HELPP
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Answer:Correct answer: 15.85 kg·m/s

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Convert the following dB to decimal a. -12 b. 3 c. 10 d. 0
stiks02 [169]

Answer:

for -12db

 \frac{V1}{V2}=0.251\\\\\frac{P1}{P2}=0.0631

for 3db

\frac{V1}{V2}=\sqrt{2}\\\\\frac{P1}{P2}=2

for 10db

\frac{V1}{V2}=3.16\\\\\frac{P1}{P2}=10

for 0db

\frac{V1}{V2}=1\\\\\frac{P1}{P2}=1

Explanation:

The decibel is a logaritmic value given by:

db=10*log(\frac{P1}{P2})=20*log(\frac{V1}{V2})

we use 10 for power values and 20 for other values such voltages or currents.

\frac{V1}{V2}=10^{\frac{db}{10}}\\\\\frac{P1}{P2}=10^{\frac{db}{20}}

for -12db

\frac{V1}{V2}=10^{\frac{-12}{10}}=0.251\\\\\frac{P1}{P2}=10^{\frac{-12}{20}}=0.0631

for 3db

\frac{V1}{V2}=10^{\frac{3}{10}}=\sqrt{2}\\\\\frac{P1}{P2}=10^{\frac{3}{20}}=2

for 10db

\frac{V1}{V2}=10^{\frac{10}{10}}=3.16\\\\\frac{P1}{P2}=10^{\frac{10}{20}}=10

for 0db

\frac{V1}{V2}=1\\\\\frac{P1}{P2}=1

4 0
3 years ago
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