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Crank
2 years ago
15

Only answer 13 and 15 i did 14 already

Mathematics
2 answers:
Neko [114]2 years ago
7 0

Answer:

answer to 13 is 10

answer to 15 is 2,300?

Step-by-step explanation:

Monica [59]2 years ago
6 0

Answer:

answer to 13 is 10

answer to 15 is 2,300

Step-by-step explanation:

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How to put 7/13 in simplest form
Amiraneli [1.4K]

Answer: 7/13 is already in simplest form.

Step-by-step explanation:

The sides cannot both be divided by the same number, meaning it is already in simplest form.

5 0
2 years ago
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A pentagonal prism has dimensions that are four times the dimensions of a similar pentagonal prism. So its volume is (8, 16, 64,
enyata [817]
Scale factor for volume = A^3:B^3

(1:4)^3 = 1:64. The volume is 64x bigger.
3 0
3 years ago
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A certain model of automobile is available in seven exterior colors, three interior colors, and four interior styles. In additio
VikaD [51]

Answer:

336 version

Step-by-step explanation:

To determine the total possible number of combination we will use the product rule

Total numbers of exterior colour 7

Total number of interior colour 3

Total number of interior style 4

Total number of transmission option 2

Total number of engine option 2 therefore the total combination is

7*3 *4*2*2 = 336 possible combination

6 0
3 years ago
solve the system of equations by finding the reduced row-echelon form of the augmented matrix for the system of equations. x-2y+
Alekssandra [29.7K]

Answer:

x = -5, y = -6, z = -3

Step-by-step explanation:

Given the system of three equations:

\left\{\begin{array}{l}x-2y+3z=-2\\6x+2y+2z=-48\\x+4y+3z=-38\end{array}\right.

Write the augmented matrix for the system of equations

\left(\begin{array}{ccccc}1&-2&3&|&-2\\6&2&2&|&-48\\1&4&3&|&-38\end{array}\right)

Find the reduced row-echelon form of the augmented matrix for the system of equations:

\left(\begin{array}{ccccc}1&-2&3&|&-2\\6&2&2&|&-48\\1&4&3&|&-38\end{array}\right)\sim \left(\begin{array}{ccccc}1&-2&3&|&-2\\0&-14&16&|&36\\0&-6&0&|&36\end{array}\right)\sim \left(\begin{array}{ccccc}1&3&-2&|&-2\\0&16&-14&|&36\\0&0&-6&|&36\end{array}\right)

Thus, the system of three equations is

\left\{\begin{array}{r}x+3z-2y=-2\\16z-14y=36\\-6y=36\end{array}\right.

From the last equation:

y=-6

Substitute it into the second equation:

16z-14\cdot (-6)=36\\ \\16z=36-84\\ \\16z=-48\\ \\z=-3

Substitute y = -6 and z = -3 into the first equation:

x+3\cdot (-3)-2\cdot (-6)=-2\\ \\x=-2+9-12\\ \\x=-5

7 0
3 years ago
The saucer for Roger's teacup has a radius of 3 centimeters. What is the saucer's circumference?
Fantom [35]

C=dπ and r+r=d so 3+3=6 and 6π≈18.84 so the circumference would be 18.84
7 0
3 years ago
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