All categories

4 years ago

Please help!! (Picture attached)

Physics

1 answer:

KonstantinChe [14]4 years ago

3 0

Well it is definitely answer B because when light is on for a long time it heats up a lot.the thermometer obviously went up which means the light bulb had more energy and was hotter than the start of it

You might be interested in

A 51 kg woman skis down a hill and her kinetic energy is 9.96e4 j. What is her speed?

arlik [135]

Kinetic energy of woman is given as

$KE = 9.96 \times 10^4 J$

mass of woman is given as

$m = 51 kg$

now we will have

$KE = \frac{1}{2}mv^2$

$9.96 \times 10^4 J = \frac{1}{2}(51) v^2$

$v^2 = \frac{9.96 \times 10^4}{25.5}$

$v^2 = 3.91 \times 10^3$

$v = 62.5 m/s$

8 0

4 years ago

What are atoms of the same element with different numbers of neutrons are called?

kenny6666 [7]

Answer:

Explanation:

Los átomos que tienen el mismo número de protones y electrones pero diferente número de neutrones se llaman isótopos. Los isótopos de un elemento dado tienen diferentes masas atómicas.

4 0

4 years ago

Read 2 more answers

(a) Two ions with masses of 4.39×10^−27 kg move out of the slit of a mass spectrometer and into a region where the magnetic fiel

sammy [17]

Answer:

Part a)

$R_1 = 0.072 m$

Part b)

$R_2 = 0.036 m$

Part c)

d = 0.072 m

Explanation:

Part a)

As we know that the radius of the charge particle in constant magnetic field is given by

$R = \frac{mv}{qB}$

now for single ionized we have

$R_1 = \frac{(4.39\times 10^{-27})(7.92 \times 10^5)}{(1.6 \times 10^{-19})(0.301)}$

$R_1 = 0.072 m$

Part b)

Similarly for doubly ionized ion we will have the same equation

$R = \frac{mv}{qB}$

$R_2 = \frac{(4.39\times 10^{-27})(7.92 \times 10^5)}{(3.2 \times 10^{-19})(0.301)}$

$R_2 = 0.036 m$

Part c)

The distance between the two particles are half of the loop will be given as

$d = 2(R_1 - R_2)$

$d = 2(0.072 - 0.036)$

$d = 0.072 m$

6 0

3 years ago

A baseball player was hit by a baseball in the left eye and complains of double vision. What should you do? A. Restrict spinal m

Alex

I think the smartest answer would be C sorry if i’m writing though

4 0

4 years ago

Read 2 more answers

Find the radius RRigel of the star Rigel, the bright blue star in the constellation Orion that radiates energy at a rate of 2.7×

Lera25 [3.4K]

Answer:

$r=5.1\times10^{10}m$

Explanation:

The Stefan–Boltzmann law for a black body (as stars are treated) can be written as $j^*=\sigma T^4$ , where $j^*$ is the total energy radiated per unit surface area across all wavelengths per unit time, $T$ the absolute temperature and $\sigma=5.67\times10^{-8} Wm^{-2}K^{-4}$ is the Stefan–Boltzmann constant.

If we multiply $j*$ by the surface area $A$ of the star we get the total energy radiated across all wavelengths per unit time, which is the total power radiated, so we can write:

$P=Aj^*=A\sigma T^4=4\pi r^2\sigma T^4$

where we have used the formula for the surface area of a sphere $A=4\pi r^2$

Solving for r we have:

$r=\sqrt{\frac{P}{4\pi \sigma T^4}}=\sqrt{\frac{2.7\times10^{31}W}{4\pi (5.67\times^{-8}Wm^{-2}K^{-4})(11000K)^4}}=5.1\times10^{10}m$

7 0

4 years ago