Question

Two particles with oppositely signed charges nC are placed at two of the vertices of an equilateral triangle with side length 3 m. What is the magnitude of the electric field at the third vertex of the triangle

Answer 1

The magnitude of the electric field at the third vertex of the triangle is determined as zero.

Electric field at the third vertex of the triangle

The electric field at the third vertex of the equilateral triangle due to the other charges placed on the first and second vertices is calculated as follows;

E = E(13) + E(23)

E = (kq₁)/r² + (kq₂)/r²

where;

• q1 is positive charge
• q2 is negative charge

E =  (kq₁)/r² - (kq₂)/r²

E = 0

Thus, the magnitude of the electric field at the third vertex of the triangle is determined as zero.

Learn more about electric field here: brainly.com/question/14372859

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