Run inside if you are outdoors
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Answer:
An external force is a force that acts on an object within the system from outside the system. This type of force is different than an internal force, which acts between two objects that are both within the system. The net external force combines these two definitions; it is the total combined external force
Explanation:
ig the answer is true
Answer:
= 2630.6 N.m
Explanation:
(FR)x = ΣFx = -F4 = -407 N
(FR)y = ΣFy =-F1-F2 -F3 = -510 - 306 - 501 = -1317 N
(MR)B =ΣM + Σ(±Fd)
= MA + F1(d1 +d2) + F2d2 - F4d3
= 1504 + 510(0.880+1.11) +306(1.11) - 407(0.560)
= 2630.64 N.m (counterclockwise)
Answer:
the current value is 
Explanation:
The computation of the value of the current is given below:

Hence, the current value is 
Given:
speed of 0.40meters/seconds
1,800 Newton's horizontal force
Required:
Power of the horse
Solution:
P = F(D/T) where P is power in
watts, F is the force, D is the distance and T is time
P = (1,800N) (0.40 meters/seconds)
P = 720 Watts