Answer the question in the picture make your response simple but to where it gives a full answer! I need a response ASAP!
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Actually Welcome to the concept of Efficiency.
Here we can see that, the Input work is given as 2.2 x 10^7 J and the efficiency is given as 22%
The efficiency is => 22% => 22/100.
so we get as,
E = W(output) /W(input)
hence, W(output) = E x W(input)
so we get as,
W(output) = (22/100) x 2.2 x 10^7
=> W(output) = 0.22 x 2.2 x 10^7 => 0.484 x 10^7
hence, W(output) = 4.84 x 10^6 J
The useful work done on the mass is 4.84 x 10^6 J
Hiii !!!
I am sending the soluction !!!
If you have any question, let me now =)
Jorge:)
I am sending the soluction !!!
If you have any question, let me now =)
Jorge:)