What quickly forms on a cold glass on a hot day.

The speed of supernova debris – about 15 years after Supernova 1987A exploded, its wind was seen hitting a pre-existing ring of

stira [4]

1. The speed (in light-years per year) of the debris is 4.67×10⁻² light-years / year

2. The speed (in Km/h) of the debris is 50436000 Km/h

3. The speed of light is 21.4 times the speed of the debris

<h3>What is speed? </h3>

Speed is the distance travelled per unit. Mathematically, it can be expressed as:

Speed = distance / time

<h3>How to determine the speed in light-years per year</h3>

Distance = 0.7 light-years
Time = 15 years
Speed = ?

Speed = distance / time

Speed = 0.7 / 15

Speed = 4.67×10⁻² light-years / year

<h3>2. How to determine the speed in Km/h</h3>

Speed (in light-years per year) = 4.67×10⁻² light-years / year
Speed (in Km/h) = ?

1 light-years / year = 1.08×10⁹ Km/h

Therefore,

4.67×10⁻² light-years / year = 4.67×10⁻² × 1.08×10⁹

4.67×10⁻² light-years / year = 50436000 Km/h

<h3>3. Comparison of the speed of the debris with the speed of light</h3>

Speed of light = 3×10⁸ m/s
Speed of debris = 50436000 Km/h = 50436000 / 3.6 = 14010000 m/s
Comparison =?

Comparison = Speed of light / speed of debris

Speed of light / speed of debris = 3×10⁸ / 14010000

Speed of light / speed of debris = 21.4

Cross multiply

Speed of light = 21.4 × Speed of debris

Learn more about speed:

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8 0

2 years ago

What two energies does a bulldozer use

sesenic [268]

Mechanical and electrical

3 0

3 years ago

Please solve this question.

Liono4ka [1.6K]

Hello mate !!! ^-^ !!!

<h3>Answer:</h3>

(a) True

(b) False

(c) 6A – 2A = 4A.

<h3>Explanation:</h3>

(a) As we can see in the above given circuit diagram is parallel connection. So, A is 6A.

The current is distributed of each wire in the same quantity which is = 2A. ( So, 2A × 3 = 6A ).

(b) Since, it's a parallel connection, all electrons will flow equally to each connection connected to bulb and ammeter. So, if bulb B3 is blown away, the other two bulb will continue the same glow as before as previous glow they have there.

(c) As one bulb will blow away, take an example if bulb B1 is blown away, The affect on ammeter 'A' reading will be = 2A + 2A = 4A.

4 0

2 years ago

On a snowy day, max (mass = 15 kg) pulls his little sister maya in a sled (combined mass = 20 kg) through the slippery snow. max

sesenic [268]

Work done by a given force is given by

$W = F.d$

here on sled two forces will do work

1. Applied force by Max

2. Frictional force due to ground

Now by force diagram of sled we can see the angle of force and displacement

work done by Max = $W_1 = Fdcos\theta$

$W_1 = 12*5cos15$

$W_1 = 57.96 J$

Now similarly work done by frictional force

$W_2 = Fdcos\theta$

$W_2 = 4*5cos180$

$W_2= -20 J$

Now total work done on sled

$W_{net}= W_1 + W2$

$W_{net} = 57.96 - 20 = 37.96 J$

7 0

4 years ago

Which of the following is a good conductor of heat? 1. water 2. glass 3. wood 4. mercury

trapecia [35]

Answer:

So the answer would be water based on the evidence shown below.

Explanation:

Mercury is a poor conductor of heat but good for electricity, water is a good conductor of heat but a poor conductor of electricity, wood is a poor conductor of heat and electricity, and glass is probably the worst conductor of heat.

7 0

3 years ago