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Goryan [66]
4 years ago
13

A train at rest emits a sound at a frequency of 1057 Hz. An observer in a car travels away from the sound source at a speed of 2

0.6 m/s. What is the frequency heard by the observer
Physics
1 answer:
il63 [147K]4 years ago
4 0

Answer:

993.52 Hz

Explanation:

The frequency of sound emitted by the stationery train is 1057 Hz.

The car travels away from the train at 20.6 m/s.

The frequency the observer hears is given by the formula:

f_o = \frac{v - v_o}{v}f

where v = velocity of sound = 343 m/s

vo = velocity of observer

f = frequency from source

This phenomenon is known as Doppler's effect.

Therefore:

f_o = \frac{343 - 20.6}{343} * 1057\\ \\f_o = 322.4 / 343 * 1057\\\\f_o = 993.52 Hz

The frequency heard by the observer is 993.52 Hz.

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A uniform meterstick in static rotational equilibrium when a mass of 220 g is suspended from the 5.0 cm mark, a mass of 120 g is
KatRina [158]

Answer:

m = 170 g

Explanation:

Meter stick is suspended at 40 cm mark

So here the torque due to additional mass and torque due to weight of the spring must be counter balanced

given that

1) 220 g is suspended at x = 5 cm

2) 120 g is suspended at x = 90 cm

3) mass of the scale is acting at its mid point i.e. x = 50 cm

now with respect to the suspension point the torque must be balanced

so we have

220(40 - 5) = m(50 - 40) + 120(90 - 40)

220(35) = 10 m + 6000

by solving above equation we have

m = 170 g

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3 years ago
Find the horizontal and vertical components of a projectile that is fired with a velocity of 50m/s at 30 degrees relative to the
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3 years ago
A block with mass of 10 kg is on a frictionless surface. One hand on the left side of the block is pushing it to the right. A se
igomit [66]

Answer:

W_2=-12J

Explanation:

The work of force 2 will be given by the vectorial equation W_2=F_2.d. We know the value of F_1 and have information about its movement, which relates to the net force F=F_1+F_2.

About this movement we can obtain the acceleration using the equation v_f^2=v_i^2+2ad. Since it departs from rest we have a=\frac{v_f^2}{2d}.

And then using Newton's 2dn Law we can obtain the net force F=ma, thus we will have F_2=F-F_1=ma-F1=\frac{mv_f^2}{2d}-F_1

And we had the work done by force 2 as:

W_2=F_2.d=\frac{mv_f^2}{2}-F_1d

(The sign will be given algebraically since we take positive the direction to the right.)

With our values:

W_2=\frac{(10kg)(2m/s)^2}{2}-(8N)(4m)=-12J

<em>Another (shorter but maybe less intuitive way for someone who is learning) way of doing this would have been to say that the work done by both forces would be equal to the variation of kinetic energy:</em>

<em>W_1+W_2=K_f-K_i=K_f=\frac{mv_f^2}{2}</em>

<em>Which leads us to the previous equation straightforwardly.</em>

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3 years ago
A parallel plate capacitor can store
Norma-Jean [14]
A parallel plate capacitor can store electric charge and
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3 years ago
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Higher Current = ________ Moving Electric Charges (Electrons) *
Eva8 [605]

Answer:

Higher current is normally achieved by faster moving electrons.

Explanation:

  • Current is solely not the speed of the electric charges, but speed of the electrons is one of the factors that current depends on.
  • Current is the net charge flowing per unit time.
  • Current can be represented by:

            I=v×e×N×A

where,

                  I= current

                  e= electric charge

                  v= speed of electrons

                  N=no. of free electric charges per volume

  • The unit of current is Ampere, represented by A. It is flow of 1 coulomb of charge in 1 second.
7 0
3 years ago
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