A train at rest emits a sound at a frequency of 1057 Hz. An observer in a car travels away from the sound source at a speed of 2
1 answer:
Answer:
993.52 Hz
Explanation:
The frequency of sound emitted by the stationery train is 1057 Hz.
The car travels away from the train at 20.6 m/s.
The frequency the observer hears is given by the formula:
where v = velocity of sound = 343 m/s
vo = velocity of observer
f = frequency from source
This phenomenon is known as Doppler's effect.
Therefore:
The frequency heard by the observer is 993.52 Hz.
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Answer:
magnification will be -0.025
Explanation:
We have given the radius of curvature = 12 cm
And object distance = 3 m
So focal length
Now for mirror we know that
So
v = 0.750 m
Now magnification of the mirror is
Answer:
(a) a = 2.44 m/s²
(b) s = 63.24 m
Explanation:
(a)
We will use the second equation of motion here:
where,
s = distance covered = 47 m
vi = initial speed = 0 m/s
t = time taken = 6.2 s
a = acceleration = ?
Therefore,
<u>a = 2.44 m/s²</u>
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(b)
Now, we will again use the second equation of motion for the complete length of the inclined plane:
where,
s = distance covered = ?
vi = initial speed = 0 m/s
t = time taken = 7.2 s
a = acceleration = 2.44 m/s²
Therefore,
<u>s = 63.24 m</u>
Answer:
= 591.45 T/s
Explanation:
i = induced current in the loop = 0.367 A
R = Resistance of the loop = 117 Ω
E = Induced voltage
Induced voltage is given as
E = i R
E = (0.367) (117)
E = 42.939 volts
= rate of change of magnetic field
A = area of loop = 7.26 x 10⁻² m²
Induced emf is given as
= 591.45 T/s
To answer this question do you need to know the formula to get the rate of change of acceleration (a=Δv/Δt; Δv= final velocity - initial velocity) and the formula to find the force of an object given a constant acceleration (F=m*a). Given these two formulas you can applicate them to solve for the mass of an object.
