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ludmilkaskok [199]
3 years ago
10

A.) A hardworking ant must supply 0.0650 N to pull a piece of fruit at constant velocity 8.40 cm up the colony's ant hill. If th

e coefficient of kinetic friction between the piece of fruit and the 24.0° sloped ant hill is 0.420, calculate the work done by the ant by pulling the piece of fruit up the hill.
B.) Use the work-energy theorem to calculate the mass of the piece of fruit in grams. (The acceleration due to gravity is 9.81 m/s2.)
Physics
1 answer:
barxatty [35]3 years ago
5 0

Answer:

a). W_{a}=5.46x10^-3 J

b). m=287.78g

Explanation:

a)

The work done by the hardworking ant is the same work in the direction of the plane so

W_{a}=F*d

W_{a}=0.0650N*84.0x10^-3m

W_{a}=5.46x10^-3 J

b)

Using the theorem of work energy and conservation can find the mass of the piece of fruit

W_{a}=E_{k}+E_{p}+W_{fk}

E_{k}=0

E_{p}=m*g*h

W_{k}=u*N

W_{a}=0+m*g*d*sin(24)-u*m*g*d*cos(24)

W_{a}=m*g*d*(sin(24)-u*cos(24))

Resolve to m

m=\frac{W_{a}}{g*d*(sin(24)-u*cos(24)}

m=\frac{5.46x^-3J}{9.81m/s^2*84.0x10^-3*(sin(24)-0.420*cos(24)}

m=0.2877 kg \frac{1000g}{1kg}=287.78g

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An olympic high diver has gravitational potential energy because of her height. as she dives, what becomes of her energy just be
sammy [17]

An Olympic high diver has gravitational potential energy because of her height. As she dives, kinetic energy becomes of her energy just before she hits the water.

Gravitational potential energy is the energy possessed or acquired by an object due to a change in its position when it is present in a gravitational field. In simple terms, it can be said that gravitational potential energy is an energy that is related to gravitational force or to gravity.

Kinetic energy is the energy of motion, observable as the movement of an object, particle, or set of particles.

When the high diver is standing stable and not moving , that diver has a gravitational potential energy because of the height . The moment she dives , before hitting the water , from being stationary she gained some momentum and come in motion , due to motion her gravitational potential energy will change to kinetic energy before hitting the ground.

To learn more about Gravitational potential energy  here

brainly.com/question/15978356

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6 0
1 year ago
A Navy vessel is traveling due north during wartime. A torpedo has been launched by an enemy directly toward the stern (rear) of
Anika [276]

Answer:

The correct option is;

B) No, the Navy vessel is slower

Explanation:

The speed of some torpedoes can be as high as 370 km/h. The average speed of a fast Navy vessel is approximately 110 km/h

Therefore, the torpedoes travel approximately 3 times as fast as the (slower) Navy vessel, such that the torpedo covers three times the distance of the Navy vessel in the same time and therefore, if the Navy vessel and the torpedo continue in a straight line (in the same direction) due north the vessel can not outrun the torpedo

Therefore, no the Navy vessel travels slower than a torpedo.

8 0
2 years ago
Block 1, of mass m₁ = 1.30 kg , moves along a frictionless air track with speed v₁ = 29.0 m/s. It collides with block 2, of mass
Alecsey [184]

Answer:

a. 37.7 kgm/s b. 0.94 m/s c. -528.85 J

Explanation:

a. The initial momentum of block 1 of m₁ = 1.30 kg with speed v₁ = 29.0 m/s is p₁ = m₁v₁ = 1.30 kg × 29.0 m/s = 37.7 kgm/s

The initial momentum of block 2 of m₁ = 39.0 kg with speed v₂ = 0 m/s since it is initially at rest is p₁ = m₁v₁ = 39.0 kg × 0 m/s = 0 kgm/s

So, the magnitude of the total initial momentum of the two-block system = (37.7 + 0) kgm/s = 37.7 kgm/s

b. Since the blocks stick together after the collision, their final momentum is p₂ = (m₁ + m₂)v where v is the final speed of the two-block system.

p₂ = (1.3 + 39.0)v = 40.3v

From the principle of conservation of momentum,

p₁ = p₂

37.7 kgm/s = 40.3v

v = 37.7/40.3 = 0.94 m/s

So the final velocity of the two-block system is 0.94 m/s

c. The change in kinetic energy of the two-block system is ΔK = K₂ - K₁ where K₂ = final kinetic energy of the two-block system = 1/2(m₁ + m₂)v² and K₁ = final kinetic energy of the two-block system = 1/2m₁v₁²

So, ΔK = K₂ - K₁ = 1/2(m₁ + m₂)v² - 1/2m₁v₁² = 1/2(1.3 + 39.0) × 0.94² - 1/2 × 1.3 × 29.0² = 17.805 J - 546.65 J = -528.845 J ≅ -528.85 J

7 0
3 years ago
What factors determine climate?
const2013 [10]

Answer:

here

Explanation:

Climate is determined by the temperature and precipitation characteristics of a region over time. The temperature characteristics of a region are influenced by natural factors such as latitude, elevation and the presence of ocean currents.

3 0
3 years ago
The notes produced by a tuba range in frequency from approximately 45 Hz to 375 Hz. Find the possible range of wavelengths in ai
taurus [48]

Answer:

The possible range of wavelengths in air produced by the instrument is 7.62 m and 0.914 m respectively.

Explanation:

Given that,

The notes produced by a tuba range in frequency from approximately 45 Hz to 375 Hz.

The speed of sound in air is 343 m/s.

To find,

The wavelength range for the corresponding frequency.

Solution,

The speed of sound is given by the following relation as :

v=f_1\lambda_1

Wavelength for f = 45 Hz is,

\lambda_1=\dfrac{v}{f_1}

\lambda_1=\dfrac{343}{45}=7.62\ m

Wavelength for f = 375 Hz is,

\lambda_2=\dfrac{v}{f_2}

\lambda_2=\dfrac{343}{375}=0.914\ m/s

So, the possible range of wavelengths in air produced by the instrument is 7.62 m and 0.914 m respectively.

6 0
3 years ago
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