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3 years ago

Express 75−−√ in the form ab√.

1 answer:

8 0

We can write 75 = 25 x 3
and √75 = √ (25 x 3) = √25 x √3
Now we know that square root of 25 is 5 a 5x5 = 25
so we can express this in the form of 5√3.

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Answer:

Detailed solution is given below

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3 years ago

6. One minute after takeoff, a rocket carrying the space shuttle into outer space reaches a speed of 447 m/s.

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Answer:

acceleration of the rocket is given as

$a = 7.45 m/s^2$

Explanation:

As we know that rocket starts from rest and then reach to final speed of 447 m/s after t = 1 min

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$v_i = 0$

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2 years ago

What measures the amount of displacement in a transverse wave

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2 years ago

Which property of a substance is not affected by physical changes?

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3 years ago

The linear charge density on the inner conductor is and the linear charge density on the outer conductor is

Lubov Fominskaja [6]

Complete Question

The complete question is shown on the first uploaded image (reference for Photobucket )

Answer:

The electric field is $E = -1.3 *10^{-4} \ N/C$

Explanation:

From the question we are told that

The linear charge density on the inner conductor is $\lambda _i = -26.8 nC/m = -26.8 *10^{-9} C/m$

The linear charge density on the outer conductor is

$\lambda_o = -60.0 nC/m = -60.0 *10^{-9} \ C/m$

The position of interest is r = 37.3 mm =0.0373 m

Now this position we are considering is within the outer conductor so the electric field at this point is due to the inner conductor (This is because the charges on the conductor a taken to be on the surface of the conductor according to Gauss Law )

Generally according to Gauss Law

$E (2 \pi r l) = \frac{ \lambda_i }{\epsilon_o}$

=> $E = \frac{\lambda _i }{2 \pi * \epsilon_o * r}$

substituting values

$E = \frac{ -26 *10^{-9} }{2 * 3.142 * 8.85 *10^{-12} * 0.0373}$

$E = -1.3 *10^{-4} \ N/C$

The negative sign tell us that the direction of the electric field is radially inwards

=> $|E| = 1.3 *10^{-4} \ N/C$

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3 years ago