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slavikrds [6]
3 years ago
5

a toboggan loaded with vacationing students (total weight 1300 N) slides down a slope at 30 degrees and there is no friction. wh

at is the acceleration of the toboggan?
Physics
1 answer:
sasho [114]3 years ago
4 0

Answer:

The acceleration of the sliding toboggan is, a = 4.9 m/s²

Explanation:

Given data,

The total weight of the toboggan, W = 1300 N

The slope is, Ф = 30°

The acceleration of a body under the influence of the gravitational field does not depend on its mass, size and shape in the absence of the air resistance.

Therefore,

The acceleration of the toboggan is given by the formula,

                           a = g Sin Ф

Substituting the given values in the above equation,

                           a = 9.8 x Sin 30°

                              = 4.9 m/s²

Hence, the acceleration of the sliding toboggan is, a = 4.9 m/s²

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A manufacturer supplies plastic cups that are placed under the legs of the chair. The manufacturer's claim is that there will be no marks of chair due to pushing or pulling on the floor.

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A manufacturer is a person who converts his idea of developing and constructing any item using some set of machines.

A manufacturer supplies plastic cups that are placed under the legs of the chair.

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What form of energy is released into the atmosphere by the earth's surface
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A solution is prepared by dissolving 17.75 g sulfuric acid, h2so4, in enough water to make 100.0 ml of solution. if the density
Yuliya22 [10]

The solution of Sulfuric Acid (H2SO4) has the following mole fractions:

  • mole fraction (H2SO4)= 0.034
  • mole fraction (H2O)= 0.966

To solve this problem the formula and the procedure that we have to use is:

  • n = m / MW
  • = ∑ AWT
  • mole fraction = moles of A component / total moles of solution
  • ρ = m /v

Where:

  • m = mass
  • n = moles
  • MW = molecular weight
  • AWT = atomic weight
  • ρ = density
  • v = volume

Information about the problem:

  • m solute (H2SO4) = 17.75 g
  • v(solution) = 100 ml
  • ρ (solution)= 1.094 g/ml
  • AWT (H)= 1 g/mol
  • AWT (S) = 32 g/mol
  • AWT (O)= 16 g/mol
  • mole fraction(H2SO4) = ?
  • mole fraction(H2O) = ?

We calculate the moles of the H2SO4 and of the H2O from the Pm:

MW = ∑ AWT

MW (H2SO4)= AWT (H) * 2 + AWT (S) + AWT (O) * 4

MW (H2SO4)= (1 g/mol * 2) + (32,064 g/mol) + (16 g/mol * 4)

MW (H2SO4)= 2 g/mol + 32 g/mol + 64 g/mol

MW (H2SO4)=  98 g/mol

MW (H2O)= AWT (H) * 2 + AWT (O)

MW (H2O)= (1 g/mol * 2) + (16 g/mol)

MW (H2O)= 2 g/mol + 16 g/mol

MW (H2O)=  18 g/mol

Having the Pm we calculate the moles of H2SO4:

n = m / MW

n(H2SO4) = m(H2SO4) / MW (H2SO4)

n(H2SO4) = 17.75 g / 98 g/mol

n(H2SO4) = 0.1811 mol

With the density and the volume of the solution we get the mass:

ρ(solution)= m(solution) /v(solution)

m(solution) = v(solution) * ρ(solution)

m(solution) = 100 ml * 1.094 g/ml

m(solution) = 109.4 g

Having the mass of the solution we calculate the mass of the water in the solution:

m(H2O) = m(solution) - m solute (H2SO4)

m(H2O) = 109.4 g - 17.75 g

m(H2O) = 91.65 g

We calculate the moles of H2O:

n = m / MW

n(H2O) = m(H2O) / MW (H2O)

n(H2O) = 91.65 g / 18 g/mol

n(H2O) = 5.092  mol

We calculate the total moles of solution:

total moles of solution = n(H2SO4) + n(H2O)

total moles of solution = 0.1811 mol + 5.092  mol

total moles of solution = 5.2731 mol

With the moles of solution we can calculate the mole fraction of each component:

mole fraction (H2SO4)= moles of (H2SO4) / total moles of solution

mole fraction (H2SO4)= 0.1811 mol / 5.2731 mol

mole fraction (H2SO4)= 0.034

mole fraction (H2O)= moles of (H2O) / total moles of solution

mole fraction (H2O)= 5.092  mol / 5.2731 mol

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<h3>What is a solution?</h3>

In chemistry a solution is known as a homogeneous mixture of two or more components called:

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8 0
1 year ago
You are trying to hear your friend give directions to new store in town. But from your distance (1 point) of 15 m you only hear
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Answer:

option D

Explanation:

given,

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distance = 15 m

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distance between the sound level = ?

Using relation

L_2 = L_1 - |20(log \dfrac{r_2}{r_1})|

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log (\dfrac{r_2}{r_1}) = \dfrac{L_1 -L_2}{20}

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r₂ = 0.47 m

r₂ = 47 cm

hence, the correct answer is option D

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3 years ago
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