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Anettt [7]
3 years ago
8

What must be the units for the gravitational constant G in order for gravitational force to have units of newtons?

Physics
1 answer:
babunello [35]3 years ago
4 0

Answer:

m³/(kg⋅s²)

Explanation:

Hello.

In this case, since the involved formula is:

F=G*\frac{m_1m_2}{r^2}

By writing a dimensional analysis with the proper algebra handling, we obtain:

N[=]G*\frac{kg*kg}{m^2}\\ \\kg*\frac{m}{s^2}[=]G *\frac{kg*kg}{m^2}\\\\G[=]\frac{kg*m*m^2}{kg^2*s^2}\\ \\G[=]\frac{m^3}{kg*s^2}

Thus, answer is:

m³/(kg⋅s²)

Note that the [=] is used to indicate the units of G.

Best regards

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Lena [83]

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6.77 m/s

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First, in the x direction:

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Δx = 3.17 m

v₀ = v cos 30.8° = 0.859 v

a = 0 m/s²

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(3.17 m) = (0.859 v) t + ½ (0 m/s²) t²

3.17 = 0.859 v t

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Next, in the y direction:

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Δy = 0.432 m

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a = -9.81 m/s²

Δy = v₀ t + ½ at²

(0.432 m) = (0.512 v) t + ½ (-9.81 m/s²) t²

0.432 = 0.512 v t − 4.905 t²

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v = 6.77

7 0
3 years ago
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